Answer:
P(z>1.3) = 0.9032
Step-by-step explanation:
We are given:
Mean = 5000
Standard deviation = 1000
x = 6300
P(x>6300)=?
z-score =?
z-score = x- mean/standard deviation
z-score = 6300 - 5000/1000
z- score = 1300/1000
z-score = 1.3
So, P(x>6300) = P(z>1.3)
Looking at the z-probability distribution table and finding value:
P(z>1.3) = 0.9032
So, P(z>1.3) = 0.9032
Answer:
The population of a statistical survey is chose at random, so it's not believed to be biased.
Answer: Range - 12 Median - 59
Step-by-step explanation: To find the range order your numbers from least to greatest then subtract the smallest from the highest 61-49 = 12 then for the median do the same in ordering the numbers then count how many you have. The number in the middle is your median. If there is two add them and divided by two. 59. Hope this helped!
