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3 years ago

7

Which of the following has a shallower slope than the line 3x-1y=-1 ?

2 answers:

forsale [732]3 years ago

4 0

3x - y = -1
-y = -3x - 1
y = 3x + 1....slope here is 3

a shallower one would be : C, 1/5

BaLLatris [955]3 years ago

3 0

1/5 (c) since it goes up only one and then over 5

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Determine if the equation is linear. If so, graph the function.

musickatia [10]

Answer:

The equation is not linear

Step-by-step explanation:

You are given the equation

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Express y in terms of x:

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The linear function must of form

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where m and b are real numbers.

Your function is not of this form, so this is not a linear function.

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3 years ago

The answer and how you got the answer

olasank [31]

Answer:

$\frac{34}{15}$

Step-by-step explanation:

we are asked to evaluate

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

Above we are given mixed fraction which can be converted in proper fraction using formula given below

$a\tfrac{b}{c}=\frac{a \times c +b}{c}$

Hence

$4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}$

$4\tfrac{1}{4}=\frac{17}{4}$

Also

$1\tfrac{7}{8}=\frac{1 \times 8 +7}{8}$

$1\tfrac{7}{8}=\frac{15}{8}$

Hence

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

can be written as

$\frac{17}{4}$ ÷ $\frac{15}{8}$

Also we know the rule for dividing fraction is as given below

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b} \times \frac{d}{c}$

Hence

$\frac{17}{4}$ ÷ $\frac{15}{8}$ = $\frac{17}{4} \times \frac{8}{15}$

= $\frac{17 \times 2}{15}$

= $\frac{34}{15}$

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3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

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