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tatiyna
3 years ago
7

In a triangle ABC, a=4 cm, b=3 cm and angleC=30°, find the area of triangle ABC.

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
The correct answer is c
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Help much needed ✨ <br> Thank you
Radda [10]
1 = 64
2 = 44
3 = 5 over 1
3 0
3 years ago
Read 2 more answers
Can someone give me the answer
Lelechka [254]
Hi,


The answer is D, (y = 8x)


Hope this helps.
r3t40

5 0
3 years ago
MNOP is similar to QRST with a scale factor of 5 : 4. MP = 85mm. What is the value of QT?
chubhunter [2.5K]
MNOP is similar to QRST with ratio of 5:4<span>. That means the MP:QT ratio would also be 5:4

The length of QT would be
</span>MP/QT = 5/4<span>
85mm/QT=5/4
85mm*4= 5*QT
5QT= 340
QT=68mm</span>
8 0
4 years ago
The amount of fence a farmer needs to create a garden with width w and length l is f = 5w + 21.
Nonamiya [84]

The formula that represents l in terms of f and w is l = (f-5w)/2

<h3>Subject of formula </h3>

This is way of representing a variable with other variables in an expression, Given the expression that represent the amount of fence a farmer needs to create a garden with width w and length

f = 5w + 2l

Make l the subject of the formula

2l = f - 5w

Divide both sides by 2

2l/2 = (f-5w)/2

l = (f-5w)/2

Hence the formula that represents l in terms of f and w is l = (f-5w)/2

Learn more on subject of formula here: brainly.com/question/657646

#SPJ1

8 0
2 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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