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Sergeeva-Olga [200]
3 years ago
9

F(x) = x2. What is g(x)?

Mathematics
1 answer:
il63 [147K]3 years ago
3 0
C because I did this on my test too
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What is X. PLEASE HELP I GIVE BRAINLEIEST
Mademuasel [1]

Answer:

x=60

Step-by-step explanation:

Hope this helped.

8 0
3 years ago
Dawn is ordering 1 veggie sandwich for every 3 ham sandwiches. She needs 12 sandwiches in all. Veggie sandwiches cost 4.00 dolla
NISA [10]

Answer:

$52.50

Step-by-step explanation:

Lets use V for Veggie, and H for Ham.

V=4

H=4.50

She is getting 12 sandwiches, and Every 3 H, she buys one V.

So, the order of her buying the sandwiches would be:

H H H V H H H V H H H V

9 H and 3 V

9*H=40.5

3*V=12

40.5+12= $52.50

5 0
3 years ago
Determine which postulate can be used
Kruka [31]

Answer:

SAS postulate

Step-by-step explanation:

The triangles have two congruent sides and one congruent angle. The congruent angle is the included angle. This meets SAS criteria.

<u>Hope this helps :-)</u>

3 0
3 years ago
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ &#10;(2) \ ln \  b^{a} = a*ln \ b \\&#10;(3) \ ln \ a + ln \ b = ln \ (ab) \\&#10;(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
ln \ x + ln \  x^{2} = ln \  8^{2}  ⇒⇒⇒⇒ rule (1) and rule (2)

ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
Read 2 more answers
If the two angles are complementary, find the measure of each of angle. I am having trouble decoding this problem in it it says
telo118 [61]

Answer:

f=10

Step-by-step explanation:

I don't know a formula for this but I can see that <CRE is a 90° angle so 7f+2f=90 and if f=10 7f=70 and 2f=20 which fits

3 0
3 years ago
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