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Dima020 [189]
3 years ago
14

When creating lines of best fit, do you believe that estimation by inspection of the equation is best or do you think it should

be determined exactly? In what situations would it be best to use one over the other?
Mathematics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

Estimation by inspection is better than trying to determine the line of best fit exactly

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

Step-by-step explanation:

To create lines of best fit the estimation by inspection is better than trying to determine the line of best fit exactly .

This is because line of best fit only shows the trend of the data and in most cases it doesn't have to start from origin.

Scenarios :

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

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F(x)=4x+1<br> g(x)=−4x−1<br> Write g in terms of f
Assoli18 [71]

Answer:

i think that the answers is -16x + 5

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3 years ago
Michael has a total of 15 bills that are either $1 bills or $5 bills. If the total amount of money he has is $47, how many $5 bi
HACTEHA [7]
He has 8 five dollar bills and 2 dollar bills.
3 0
2 years ago
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During a science experiment,the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in
GaryK [48]
Answer:
5 degrees

Step-by-step explanation:

We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
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According to question
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Hence, the temperature of solution in a beaker 2=5 degrees
7 0
11 months ago
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expeople1 [14]

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Step-by-step explanation:

To square a number, you multiply it by itself twice.

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Hope it helps! :)

3 0
3 years ago
The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is
saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

   α = 0.05, α/2 = 0.025

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 (32.52, 35.8)

 95% confidence interval is  (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.  

4 0
2 years ago
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