Question

What is the difference of the rational expressions below? 4/x^3 - 2x-1/3x

Answer 1

Answer:

C

Step-by-step explanation:

Given

$\frac{4}{x^3}$ - $\frac{2x-1}{3x}$

Multiplying the numerator/ denominator of the first fraction by 3 and the numerator/denominator of the second fraction by x² will ensure that the fractions have a common denominator.

= $\frac{3(4)}{3x^3}$ - $\frac{x^2(2x-1)}{3x^3}$

= $\frac{12}{3x^3}$ - $\frac{2x^3-x^2}{3x^3}$ ← combine terms on numerator

= $\frac{12-2x^3+x^2}{3x^3}$

= $\frac{-2x^3+x^2+12}{3x^3}$ → C