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ValentinkaMS [17]
3 years ago
15

The ratio of the number of girls to the number of boys was 4 to 5 if 1,530 students were present how many were girls and how man

y were boys?
Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

the answer will be

girls 680

boys 850

vlada-n [284]3 years ago
4 0

Answer:

680 girls and 850 boys

Step-by-step explanation:

the ratio of girls is 4/9

then we can find the number of girls (G) in the group of 1530 students using proportions:

4 / 9 = G / 1530

solving for G by multiplying both sides of the proportion by 1530, we get:

G = 4 * 1530 / 9 = 680

So there were:

680 girls and 1530 - 680 = 850 boys

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Answer:

8y^6

262 144y

Step-by-step explanation:

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3 years ago
3x + 2 = 14<br> Which number makes the equation true?<br><br> 1<br> 2<br> 2<br> 4<br> 6
mrs_skeptik [129]

Answer:

x=4

Step-by-step explanation:

3x+2=14\\\\3x+2-2=14-2\\\\3x=12\\\\\displaystyle \frac{3x}{3}=\frac{12}{3}\\ \\ x=4

7 0
2 years ago
Can someone help me with this problem pleasee
Nikitich [7]

Answer:

v=8

Step-by-step explanation:

Let's solve your equation step-by-step.

16v−9v=56

Step 1: Simplify both sides of the equation.

16v−9v=56

16v+−9v=56

(16v+−9v)=56(Combine Like Terms)

7v=56

7v=56

Step 2: Divide both sides by 7.

7v

7

=

56

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hope this helps!

6 0
3 years ago
Read 2 more answers
EVALUATE THE FOLLOWING   -15 x 6​
Nat2105 [25]

the answer is 90

Step-by-step explanation:

I used a calculator so-

6 0
3 years ago
Which point would be a solution to the system of linear inequalities shown below? y&gt;4 x-5\hspace{50px}y\ge\frac{3}{5} x-1 y&g
Sauron [17]

Answer:

x < \frac{20}{17} and y \ge \frac{-5}{17}

Step-by-step explanation:

Given

y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1

Required

Find x and y

In the second equation. Assume that:

y = \frac{3}{5}x - 1\\

Substitute y = \frac{3}{5}x - 1 in the first equation

y > 4x - 5

\frac{3}{5}x - 1 > 4x - 5

Collect like terms

\frac{3}{5}x - 4x >  - 5 + 1

\frac{3}{5}x - 4x >  -4

Multiply through by 5

3x - 20x > -20

-17x > -20

Solve for x

x < \frac{20}{17}

Substitute this value of x in y \ge \frac{3}{5}x - 1

y \ge \frac{3}{5}*\frac{20}{17} - 1

y \ge \frac{3}{1}*\frac{4}{17} - 1

y \ge \frac{12}{17} - 1

y \ge \frac{12- 17}{17}

y \ge \frac{-5}{17}

3 0
3 years ago
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