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Butoxors [25]
3 years ago
14

Fraction is equivalent to a terminating decimal

Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0
The best way to compare fractions would be to make them have like denominators.  We first , in this case, need to convert from decimal to fraction. 

                 Converting decimals to fractions first requires an understanding of the decimal places that fall after the decimal.  One place after the decimal is the tenths place.  If you have a decimal that ends at one place after the decimal (or in the tenths place) it can be written as the number after the decimal in the top of the fraction and ten (tenths place) in the denominator.  ex.   .5 ends one place after the decimal and can be written as 5/10...(read as five tenths).

If a decimal ends at two places after the decimal...(ex.   .75)...it ends in the hundredths place, can be written as that number in the numerator and 100 in the denominator....(ex  75/100) and is read as seventy-five hundredths. 

one place after the decimal is tenths (over 10), two places is hundredths (over 100), three places is thousandths (over 1000) , four places ten-thousandths (over 10000) and so on.

Because each decimal in your problem has a different amount of decimal places, it makes for different denominators. But, We can add a zero to the end of a decimal without changing it's value; if we add a zero to the end of .5 and make it .50 , we then can write it as 50/100 and would now have like denominators.

if .5 = .50 = 50/100 and .75 = 75/100

we now have the question what fractions can fall between 50/100 and 75/100. 

That would be fractions such as 51/100, 52/100, 53/100.......74/100.


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Use this equation to solve the problem:

x - (x * .25) = 40

This equation is saying the original price times itself by 25% is 40.

x - (x * .25) = 40
Simplify.
x - .25x = 40
.75x = 40
Divide both sides by .75.
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The original price was $53.33
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A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?
Elza [17]
<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be m.

Let the number of dark chocolates be d.

Given that the box contains the milk and dark chocolates in the ratio 3:4.

So,\frac{m}{d}=\frac{3}{4}               ...(i)

Given that the total number of chocolates are 42.

So,m+d=42.                                   ...(ii)

Using (i) and (ii),

m+\frac{4}{3}m=42

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m=18

d=\frac{4}{3}m=\frac{4}{3}\times 18=24

So,the number of milk chocolates are 18 and the number of dark chocolates are 24.

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3 years ago
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Answer:

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Step-by-step explanation:

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