A function f(x) has solutions if we can find a value to plug in that leads to 0. In other words, there are solutions to f(x) = 0. Another term for "solution" is "root" or "x intercept"
An exponential function may cross the x axis at one point only. Though there are plenty of cases when there are no solutions at all. For instance, in the case of f(x) = (2^x) + 10
The right hand side will never be equal to zero no matter what you plug in for x. The graph will never cross the axis.
To answer your question, yes it is possible to have an exponential equation to have no solutions.
The answer should be if I am correct
h times 5.25
Answer: Part A is 2 and 6 Part B is 2
Step-by-step explanation:
Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.
Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8. 3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.
Ok so i just did 56/14 and got 4. So this means 14 goes into 56 4 times, so now i did 4 x 2 and got 8. So the answer is 8 free cones.
