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elixir [45]
3 years ago
13

A number is k units to the left of 0 on the number line . Describe the location of its opposite

Mathematics
1 answer:
shusha [124]3 years ago
8 0
The opposite of left is right, so the number opposite k is k units to the right.
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What is 3,4,5 plz and thank you
Tcecarenko [31]
For 3 it’s b. For 2 it’s 8. For 4 it’s the whole number
8 0
3 years ago
Prove that if b is a square matrix then b+b^t is symmetric
WARRIOR [948]
A matrix \mathbf X is symmetric if \mathbf X=\mathbf X^\top. We have

(\mathbf B+\mathbf B^\top)^\top=\mathbf B^\top+(\mathbf B^\top)^\top=\mathbf B^\top+\mathbf B=\mathbf B+\mathbf B^\top

and so \mathbf B+\mathbf B^\top is indeed symmetric.
6 0
3 years ago
Which statement is true about this argument? premises: if an angle measure is greater than 90°, then the angle is an obtuse angl
vazorg [7]
Answer: option d. the argument is valid by the law of detachment.

The law of detachment consists in make a conlcusion in this way:

Premise 1) a => b
Premise 2) a is true

Conclusion: Then, b is true

Note: the order of the premises 1 and 2 does not modifiy the argument.

IN this case:

Premise 1) angle > 90 => obtuse

Premise 2) angle = 102 [i.e. it is true that angle > 90]]

Conclusion: it is true that angle is obtuse

3 0
3 years ago
Read 2 more answers
⦁ Evaluate ⦁ 6! ⦁ 8P5 ⦁ 12C4
lisabon 2012 [21]
6! = 6 * 5 *4*3*2*1 =720

8p5 = 8*7*6*5*4 = 6720

12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495
7 0
3 years ago
Read 2 more answers
Calculate two iterations of Newton's Method to approximate a zero of the function using the given initial guess. (Round your ans
VikaD [51]

Answer:

The two iterations of f(x) = 1.5598

Step-by-step explanation:

If we apply  Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.

xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)

Given;

f(xₙ) = cos x, then  f'(xₙ) = - sin x

cos x / - sin x = -cot x

substitute in "-cot x" into the equation

xₙ₊₁ = xₙ - (- cot x)

xₙ₊₁ = xₙ + cot x

x₁ = 0.7

first iteration

x₂ = 0.7 + cot (0.7)

x₂ =  0.7 + 1.18724

x₂ = 1.88724

 

second iteration

x₃ = 1.88724 + cot (1.88724)

x₃ = 1.88724 - 0.32744

x₃ = 1.5598

To four decimal places = 1.5598

4 0
3 years ago
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