All categories

3 years ago

8x2+4x−3 is divided by 2x−1

Mathematics

1 answer:

bagirrra123 [75]3 years ago

8 0

I hope it is helpful for you

You might be interested in

The answer to this question please

cestrela7 [59]

If its to number 9, it's ∈35.48

6 0

3 years ago

Plese help me! this is worth 25 points dont get it wrong :(

lawyer [7]

Answer:

u forgot to put up a picture :(

8 0

3 years ago

Which of the following are arranged in order from least to greatest?

spayn [35]

The correct answer is C.
Hope this helps.

7 0

3 years ago

Read 2 more answers

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

3 years ago

15y + v4-8<br> What is the degree

natulia [17]

Answer: The degree of 15y+v4-8 is 1

Step-by-step explanation: Hope this helps in your studies!

6 0

2 years ago