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IgorC [24]
3 years ago
12

- 18 10 - 11 - What’s the area of the shape and numbers ?

Mathematics
1 answer:
snow_lady [41]3 years ago
7 0

Answer:

1,980 would be the area and the perimeter would be 39 im pretty sure

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the owner of a zoo described to take a random sample of the zoos visitors to find out which exhibit was the visitor's favorite.
jok3333 [9.3K]

819 is the answer because thats how many visitors he got

7 0
3 years ago
Solve the equation for the specified variable.<br> T= BA-9, for B<br> What does b=
NARA [144]

9514 1404 393

Answer:

  B=\dfrac{T+9}{A}

Step-by-step explanation:

Add 9 to both sides of the equation, and divide by the coefficient of B.

  T = BA -9

  T +9 = BA

  (T +9)/A = B

We can rewrite that with B on the left:

  B = (T +9)/A

4 0
3 years ago
Neeta is a fourth grader. She is 4 feet 7 inches tall. When she was bom she was 17 inches long. How much has Neeta grown since s
Virty [35]

Answer:

A

Step-by-step explanation:

First, find Neeta's total height in inches:

4 feet in inches is 4*12, which equals 48

Add the other 7 inches of her height to get 55 inches.

Then, subtract her initial height from her current height.

55 - 17 = 38. That is how many inches she has grown. Convert that to feet by dividing 38 by 12.

You get about 3.16, which is over 3 feet. So A is the correct answer.

3 0
3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
Solve for b.<br> r = (b-5)m
alukav5142 [94]

Answer:

b=5m+r/m

Step-by-step explanation:

Let's solve for b.

r=(b−5)(m)

Step 1: Flip the equation.

bm−5m=r

Step 2: Add 5m to both sides.

bm−5m+5m=r+5m

bm=5m+r

Step 3: Divide both sides by m.

bm/m=5m+r/m

b=5m+r/m

Answer:

b=5m+r/m

6 0
3 years ago
Read 2 more answers
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