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Thepotemich [5.8K]
3 years ago
6

A table shows a proportional relationship where k is the constant of

Mathematics
1 answer:
Nitella [24]3 years ago
5 0
They relate because the original constant of proportionality is a unite rate. Then the flipped constant of proportionality would not be a unit rate. It's basically the reciprocal of the original constant of proportionality or K.
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PLEASEE HELPPP! <br> what is the measure of
Debora [2.8K]

Answer:

x=12

Step-by-step explanation:

Im not sure which measure you're talking about, but I'll show you what I did here:

A triangle = 180 degrees.

4x + 8x + 4x =16x

-8 - 1 - 3 = -12

180 = 16x - 12        -Add 12 to both sides

192 = 16x               -divide by 16 to get x by itself

12 = x

Angle A = 88 degrees (8 times 12 then subtract 8)

Angle B = 47 degrees (4 times 12 then subtract 1)

Angle C = 45 degrees (4 times 12 then subtract 3)

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2 years ago
Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra s
algol [13]

<em>f(x, y)</em> = <em>x</em> ² - 4<em>xy</em> + 5

has critical points where both partial derivatives vanish:

∂<em>f</em>/∂<em>x</em> = 2<em>x</em> - 4<em>y</em> = 0   ==>   <em>x</em> = 2<em>y</em>

∂<em>f</em>/∂<em>y</em> = -4<em>x</em> = 0   ==>   <em>x</em> = 0   ==>   <em>y</em> = 0

The origin does not lie in the region <em>R</em>, so we can ignore this point.

Now check the boundaries:

• <em>x</em> = 1   ==>   <em>f</em> (1, <em>y</em>) = 6 - 4<em>y</em>

Then

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 6 when <em>y</em> = 0

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -2 when <em>y</em> = 2

• <em>x</em> = 4   ==>   <em>f</em> (4, <em>y</em>) = 12 - 16<em>y</em>

Then

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 12 when <em>y</em> = 0

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -4 when <em>y</em> = 2

• <em>y</em> = 0   ==>   <em>f</em> (<em>x</em>, 0) = <em>x</em> ² + 5

Then

max{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 21 when <em>x</em> = 4

min{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 6 when <em>x</em> = 1

• <em>y</em> = 2   ==>   <em>f</em> (<em>x</em>, 2) = <em>x</em> ² - 8<em>x</em> + 5 = (<em>x</em> - 4)² - 11

Then

max{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -2 when <em>x</em> = 1

min{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -11 when <em>x</em> = 4

So to summarize, we found

max{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = 21 at (<em>x</em>, <em>y</em>) = (4, 0)

min{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = -11 at (<em>x</em>, <em>y</em>) = (4, 2)

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3 years ago
What is the chance of drawing a yellow ball then a red ball from a bag containing 3 yellow balls and 7 red balls?
Ainat [17]
Talking as if the balls do not get put back into the bag, the first probability is 3/10 for yellow. For red it will be 7/9 because there is one less ball (yellow) in the bag.
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3 years ago
How do you solve the problem attached?
pentagon [3]
Use photo math it works for all types of math and book work
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3 years ago
Read 2 more answers
PLS HALPPPPP!!!!
andrey2020 [161]

Answer:

11.01

Step-by-step explanation:

3.78+4.51+2.72=11.01

4 0
3 years ago
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