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2 years ago

A table shows a proportional relationship where k is the constant of

1 answer:

5 0

They relate because the original constant of proportionality is a unite rate. Then the flipped constant of proportionality would not be a unit rate. It's basically the reciprocal of the original constant of proportionality or K.

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Solve the following word problem. A man travels from Town X to Town Y at an average rate of 50 mph and returns at an average rat

777dan777 [17]

Distance = rate*time

Let distance from X to Y be 'd'

From the equation we can solve for 'time'

time = distance/rate

The total time it takes to go 50 mph ,then 40 mph is:

$\frac{d}{50} + \frac{d}{40}$

The total time it takes to go 45 mph round trip is:

$\frac{2d}{45}$

We know that the round-trip at 45 mph takes half-hour shorter, so by adding '1/2' to its time it will be equal to the time to go 50 then 40.

$\frac{2d}{45} + \frac{1}{2} = \frac{d}{50} + \frac{d}{40} \\ \\ \frac{4d+45}{90} = \frac{9d}{200} \\ \\ 800d+9000 = 810d \\ \\ 10d = 9000 \\ \\ d = 900$

Answer: The distance from X to Y is 900 miles.

7 0

3 years ago

Discount Rental Cars charges a daily fee plus a mileage fee for renting its cars. Barney was charged $145.00 for 3 days and 200

Finger [1]

Answer:

The charge per day is $25 and the charge per mile is $0.35

Step-by-step explanation:

Let

x -----> the charge per day

y ----> the charge per mile

we know that

3x+200y=145 -----> equation A

5x+430y=275.50 -----> equation B

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The intersection point is (25,0.35)

see the attached figure

therefore

The charge per day is $25 and the charge per mile is $0.35

6 0

3 years ago

If £1 is equal to 99.72 rupees and the post office only has 500 rupee papers how much can I change out of £450

sweet [91]

£1 = 99.72 rupees -> £450 = 44874 rupees.

As the post office only has 500 rupee papers, once we calculate out the result, we have to round down to the nearest whole number.

The amount of rupee papers we can change out is : 44874 : 500 = 89.748 (papers)
We round down to 89 papers.

7 0

1 year ago

Hlfkejfrrigije8fejfrjhbie 484hrg8vv

madreJ [45]

Answer:

i am writing it just for points

4 0

3 years ago

Read 2 more answers

Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work

Alona [7]

Answer:

$1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x for 0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

= 18x - 144 + 96

= 18x - 48 for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

$f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D: 0 ≤ x ≤ 24 → D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

= 0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

= 432 - 48

= 384

D: 0 ≤ y ≤ 384 → D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

4 0

2 years ago