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Hunter-Best [27]

2 years ago

12

A rotating sprinkler that sprays water at a radius of 7 feet is used to water a lawn. Determine the area of the lawn that is bei

ng watered. Use 3.14 for pi. Round to the nearest tenth.

1 answer:

Damm [24]2 years ago

3 0

Answer:

49Pi

Step-by-step explanation:

Area of a circle is = to pi(r)^2

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A video store is running a closeout special of 5 DVDs for $15. If the store has 42 different titles in the closeout section, how

Elenna [48]

Answer:

C. 850,668

Step-by-step explanation:

Since order doesn't matter, we use the combination equation: nCr

We first need to find n, which would be 42. Then we find r, which is 5.

We plug them into either the equation or a calculator

(42!)/(5!(42-5)!) = 850,668

4 0

3 years ago

HELP NEEDED PLEASE!

tigry1 [53]

Answer:

the answer is about 62

Step-by-step explanation:

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3 years ago

Find the value of the expression

MArishka [77]

The value would be -35.357.

8 0

2 years ago

21. A nail salon had 83 customers, 48 received a pedicure and 57 received a manicure. How many customers got both a manicure and

creativ13 [48]

Answer:

gu h-onarach tha mi a ’miannachadh gum b’ urrainn dhomh do chuideachadh, ach tha feum agam air puingean airson mo cheistean fhìn duilich!

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

2 years ago