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eimsori [14]
3 years ago
6

Which expression is equivalent to 7x – 6?

Mathematics
2 answers:
victus00 [196]3 years ago
5 0
B... juss combine like terms
Anarel [89]3 years ago
5 0

Answer:

A = 7x-6

Step-by-step explanation:

A. = 7x-6

B. = 7x-24

C. = -6+6x

D.= -8=7x

These are the simplified expressions. Obviously just by looking at them, you can see that A is the correct answer.

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Joelle is working on a school report in a word processor. She wants to place an oversized image which is 30.51 \text{ cm}30.51 c
ehidna [41]

Answer:

the horizontal position for the left edge of the image is -4.46 cm.

Step-by-step explanation:

The horizontal midpoint of the page is:

21.59 / 2 = 10.79 cm

The horizontal midpoint of the image is given as:

30.51 / 2 = 15.25 cm

These midpoints must be on the same point in the axis.

By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.  

The distance that goes beyond this leftmost edge is computed as;

This is on the negative side on the axis.

Thus the horizontal position for the left edge of the image is -4.46 cm.

3 0
3 years ago
In the figure below, what is the length of<br> MN?
Diano4ka-milaya [45]
There is no figure below.
6 0
3 years ago
What is the interquartile range of 4 5 7 9 10 14 16 24
Mama L [17]
2's and 3's of GCF


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7 0
3 years ago
Read 2 more answers
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
2 years ago
Please help me on this one question! (10th grade level)
Semmy [17]
Make an inequality representing both constraints.
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x+y≥24
for a
3 0
3 years ago
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