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mylen [45]
2 years ago
7

Twelve percent of yesterday’s customers purchased premium-grade gasoline from GasCo. If 24 customers bought premium-grade gasoli

ne, how many customers were there all together?
Mathematics
1 answer:
Oduvanchick [21]2 years ago
7 0

Answer:

196

Step-by-step explanation:

100 divided by 12 is 8 r 4 24 x 8 = 192, 192 + 4 is 196

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To support National Heart Week, the Heart Association plans to install a free blood pressure testing booth in El Con Mall for th
worty [1.4K]

Answer:

(a) Average number expected = 13.07 people

(b) Average number of persons = 14 persons

(c) Average amount of time = 0.9333 hours

(d) Time taken = 1 hour

Step-by-step explanation:

We are informed that the arrivals have a Poisson distribution from an infinite population. On average, 14 persons per hour request a test. Hence,

Arrival rate = λ = 14

Each blood pressure measurement takes 4 minutes. In 1 hour, 60 / 4 = 15 persons are served. Hence,

Service rate = μ = 15

(a) Average number in line = (λ^2) / μ(μ - λ)

                                             = (14^2) / 15(15 - 14)

                                             = 13.07

(b) Average number in system = λ / (μ - λ)

                                                   = 14 / (15 - 14)

                                                   = 14

(c) Average waiting time = Average number in line / λ

                                         = 13.07 / 14

                                         = 0.9333

(d) Average total time = Average number in system / λ

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6 0
2 years ago
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Answer: (57.41,\ 62.19)

Step-by-step explanation:

Given : Sample size : n=40

Sample mean : \overline{x}=59.8\text{ seconds}

Standard deviation : \sigma =9.2\text{ seconds}

Significance level : \alpha=1-0.9=0.1

Critical value : z_{\alpha/2}=1.645

Formula to find the confidence interval for population mean :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=59.8\pm(1.645)\dfrac{9.2}{\sqrt{40}}\\\\\approx59.8\pm2.39\\\\=(59.8-2.39,\ 59.8+2.39)\\\\=(57.41,\ 62.19)

Hence, a 90​% confidence interval estimate of the population mean of all students = (57.41,\ 62.19)

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