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3 years ago

7

Does the data suggest a linear, quadratic, or exponential model?

1 answer:

oksano4ka [1.4K]3 years ago

4 0

Exponential model because it's increasing rapidly.

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How do we multiply numbers

zavuch27 [327]

To multiply a number, simply take a number (Let's say 4) and another number (Let's say 3). If you multiply 4 by 3, you are simply taking the number 4, and adding it to itself 3 times (4 + 4 + 4).

I hope this makes sense, please tell me if you need some more information.

Hope this helps!

7 0

3 years ago

What is the answer to 40x 2/6<br> Explain how u got the answer also

Nimfa-mama [501]

The fraction form of this is 40/3, decimal form is 13.3 infinite.
Use whichever form your teacher wants you to use. (Refer to the image for the steps)

8 0

2 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

2 years ago

Read 2 more answers

Three houses for of a bag of flour to make how many bags of flour does grandma need to buy if she is making 10 dozen cookies

SCORPION-xisa [38]

Assuming you meant 3 dozen for a bag of flour the answers 4
If you meant 3 cookies for a bag of flour the answers 10

8 0

3 years ago

(75 - 7i) + (475 +7i)

Fudgin [204]

I simplified this equation and received.
Answer: 550
Elaborate what you want to solve of this is not what was wanted.

7 0

3 years ago

Read 2 more answers