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egoroff_w [7]
3 years ago
7

The Question Is Above

Mathematics
2 answers:
motikmotik3 years ago
6 0
Answer: I believe the answer is B!
Fofino [41]3 years ago
5 0

Answer:

b

Step-by-step explanation:

You might be interested in
1.55555555556 as a fraction
love history [14]
Round.

1.5555...6 rounded = 1.56

1 is a whole number
.56 is a decimal that can be changed into 56/100

1 56/100 is your answer

Hope this helps
3 0
4 years ago
Read 2 more answers
There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev
Nadusha1986 [10]
To get the total number of games possible, we will use the combination formula. 
Total number of games :  _{10}C_{2} = 45

Total of 45 games in the whole tournament.

Meanwhile, if there would be boy-versus-boy, we will have _{5}C_{2}
The answer is 10. 

The fraction for boy-versus-boy game will be 10/45 or 2/9 when simplified.
6 0
3 years ago
Which line is a graph of the equation 2x + 5y = 10?
Olenka [21]

I provided a graph which has your equation 2x+5y+10

6 0
3 years ago
If a=3b^3/c, what happens to a when b is doubled
Ratling [72]
"b" is cubed, so when you double it (2*b) the 2 also is cubed.

a = 3(2b)³/c
a = 3*8b³/c

So "a" is increased to "8a" 
4 0
3 years ago
The number of portable widgets produced weekly by Widget, Inc., is related to the weekly profit in the way:
mixer [17]

9514 1404 393

Answer:

  • 22 widgets
  • $58,400

Step-by-step explanation:

The turning point (maximum or minimum) of quadratic function ...

  f(x) = ax² +bx +c

is at x = -b/(2a).

Here, this means the maximum profit will be had when the number of widgets produced weekly is ...

  x = -88/(2(-2)) = 22

The profit at that level of production is ...

  P(22) = (-2·22 +88)(22) -384 = 44(22) -384 = 968 -384 = 584 . . . hundreds

22 widgets must be produced weekly for the maximum weekly profit of $58,400.

3 0
3 years ago
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