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Svetach [21]
3 years ago
8

Help on picture 20 points

Mathematics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

4 to 7 and 8 to 14

Step-by-step explanation:

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Can i have some help on both of these questions for brainlist !!!!!!!!!!!
Nezavi [6.7K]

Answer:

B and A

Step-by-step explanation:

What I did for these problems is plug in the numbers listed for the x-value. For example, in your calculator you’d put; (1/2)^3 and that’d get you 1/8. Then, try it for 8^(2 - 3) which is also 1/8. So, (1/2)^3 = 8^(2 - 3).

The same process for the second problem. 16^(2(7/3) -3) = 4^((7/3) + 1). This should give you 101.59…

I hope this helps :)!

5 0
2 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
in a recent season NASCAR driver Jimmie Johnson won 6 of the 36 total races held to the nearest thousand ,find the part of races
castortr0y [4]
So, the fraction of races that he won was:

\frac{6}{36} : you need ti divide the number of occurrences by the number of possibilities.

We can simplify this:
\frac{1}{6}.

When we write it in decimals until the closest place, it's:

0.167 or 16.667%


5 0
3 years ago
Read 2 more answers
What is the horizontal asympote of this graph?
Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

  • The function is undefined for x < 0, hence \lim_{x \rightarrow -\infty} f(x) is undefined.
  • For x > 0, the funciton goes to infinity, hence \lim_{x \rightarrow \infty} f(x) = \infty.

Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
Someone help.me find angle C and D<br>also this is in CIRCLE THEOREM lesson​
Artyom0805 [142]

Step-by-step explanation:

Opposite angles in a cyclic quadrilateral are supplementary.

Therefore 3c = 4d = 180°, c = 60° and d = 45°.

8 0
3 years ago
Read 2 more answers
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