Can anybody help? this is a test pleasee..!

Negative 1.5 (4 minus r) = negative 12

umka2103 [35]

Answer:

r = - 4

Step-by-step explanation:

Given

- 1.5(4 - r) = - 12 ( divide both sides by - 1.5 )

4 - r = 8 ( subtract 4 from both sides )

- r = 4 ( multiply both sides by - 1 )

r = - 4

3 0

3 years ago

Read 2 more answers

so my equation is x^2-30x=-125. i already completed the square but what does it mean when i have to add (b/2)^2

Blizzard [7]

Answer:

mh

Step-by-step explanation:

mfhnyjjjjjjjjjjjjjjjj

7 0

3 years ago

1) A rectangle has the lengths shown Find the perimeter of the rectangle.

maks197457 [2]

Hi there! :)

$\large\boxed{P = 32cm}$

Find the perimeter by solving for y.

We know that a rectangle contains two pairs of parallel and congruent sides, therefore:

5y - 1 = 2y + 8

We can solve for y using this expression. Begin by subtracting 2y from both sides:

5y - 2y - 1 = 2y - 2y + 8

3y - 1 = 8

Add 1 to both sides:

3y - 1 + 1 = 8 + 1

3y = 9

Divide both sides by 3:

y = 3

Recall that the perimeter of a rectangle is:

P = 2l + 2w

Plug in the given expressions for the side lengths to find one equation:

P = 2(5y - 1) + 2(y - 1)

Simplify by distribution:

P = 10y - 2 + 2y - 2

Combine like terms:

P = 12y - 4

Plug in the solved value of y into this equation:

P = 12(3) - 4

P = 36 - 4

P = 32 cm.

3 0

2 years ago

Miguel needs $99.95 to buy himself a pair of Beats headphones. He has 1/5 of the money saved already. How much money has he save

kumpel [21]

$19.99

1/5 = 0.20

$99.95 X 0.20 = $19.99

7 0

2 years ago

Consider the sequence {an}={3n+13n−3n3n+1}. Graph this sequence and use your graph to help you answer the following questions.

Fantom [35]

Part 1: You can simplify $a_n$ to

$\dfrac{3n+1}{3n}-\dfrac{3n}{3n+1} = \dfrac1{3n}+\dfrac1{3n+1}$

Presumably, the sequence starts at n = 1. It's easy to see that the sequence is strictly decreasing, since larger values of n make either fraction smaller.

(a) So, the sequence is bounded above by its first value,

$|a_n| \le a_1 = \dfrac13+\dfrac14 = \boxed{\dfrac7{12}}$

(b) And because both fractions in $a_n$ converge to 0, while remaining positive for any natural number n, the sequence is bounded below by 0,

$|a_n| \ge \boxed{0}$

(c) Finally, $a_n$ is bounded above and below, so it is a bounded sequence.

Part 2: Yes, $a_n$ is monotonic and strictly decreasing.

Part 3:

(a) I assume the choices are between convergent and divergent. Any monotonic and bounded sequence is convergent.

(b) Since $a_n$ is decreasing and bounded below by 0, its limit as n goes to infinity is 0.

Part 4:

(a) We have

$\displaystyle \lim_{n\to\infty} \frac{10n^2+1}{n^2+n} = \lim_{n\to\infty}10+\frac1{n^2}}{1+\frac1n} = 10$

and the (-1)ⁿ makes this limit alternate between -10 and 10. So the sequence is bounded but clearly not monotonic, and hence divergent.

(b) Taking the limit gives

$\displaystyle\lim_{n\to\infty}\frac{10n^3+1}{n^2+n} = \lim_{n\to\infty}\frac{10+\frac1{n^3}}{\frac1n+\frac1{n^2}} = \infty$

so the sequence is unbounded and divergent. It should also be easy to see or establish that the sequence is strictly increasing and thus monotonic.

For the next three, I'm guessing the options here are something to the effect of "does", "may", or "does not".

(c) may : the sequence in (a) demonstrates that a bounded sequence need not converge

(d) does not : a monotonic sequence has to be bounded in order to converge, otherwise it grows to ± infinity.

(e) does : this is true and is known as the monotone convergence theorem.

5 0

3 years ago