Can somebody help me?

The range of values for the sample mean that fall within 1 standard error of the mean in a sampling distribution is M39 to M43.

marusya05 [52]

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

The range of values for the sample mean that fall within 1 standard error of the mean in a sampling distribution is M = 39 to M = 43. What Is the mean of the sampling distribution, and what is the standard error

a) mean = 41, standard error = 2

b) mean = 39 or 43, standard error = 2

c) mean = 41, standard error = 4

e) the mean and standard error are unknowns

Given Information:

Standard error = 1

Range of values = 39 to 43

Required Information:

Mean and standard error = ?

Answer:

Mean is 41 and Standard error is 2

Explanation:

We know that the mean and standard error are related as

s = μ + (1)ο

s = μ - (1)ο

43 = μ + (1)ο

39 = μ - (1)ο

option (a) satisfies the above equations

43 = 41 + (1)2

43 = 43

39 = 41 - (1)2

39 = 39

Therefore, the correct option is (a)

Mean is 41 and standard error is 2

5 0

3 years ago

A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr

lina2011 [118]

Answer:

(a) the new angle the ladder makes with the ground is $32.7^o$

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

$sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m$

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

$sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o$

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

$cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4 \,\,m$

Now fro the new position of the bottom of the ladder relative to the wall:

$cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m$

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

4 0

3 years ago

A seamstress needs to cut 15 inches pieces of ribbon from a roll of ribbon that is 9 feet in length what is the greatest number

Natali [406]

Answer: 36

Step-by-step explanation:

One roll is of length = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

Since there are 5 rolls

So, total length of 5 rolls = 108 * 5 = 540 inches

Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.

We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon

So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:

Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36

4 0

3 years ago

Find the product (8b-8)(-2b2 - 7b + 5)

mixas84 [53]

Answer:

(8b-8)(-2b2-7b+5)= 96b-40

8 0

3 years ago

it takes Jupiter 11.9 years to orbit,or go around the sun. Saturn takes 17.6 more years than Jupiter to orbit the sun. About how

pochemuha

Saturn takes 17.6 more years than Jupiter, so 17.6 + 11.9 will get you how long Saturn will take to orbit the sun, which would give you 29.5 years.

8 0

3 years ago