There're all conjunctions.
You can seperate them in sentences after a comma for a run-on sentence.
Answer:
have the same SSID but different channels
Explanation:
Based on the information provided within the question it can be said that the best option to accomplish this would be to have the same SSID but different channels. This would maintain the users connected to the same network name (SSID) but still be able to roam and jump from one access point to the other.
According to the given question, sales is a two-dimensional array and contains 10 rows and 7 columns wherein each component is of type integer and the variables sum and j are also of integer type.
<u>Explanation:</u>
In order to find the sum of the elements of the fifth row of sales, the correct piece of code should be:
sum=0;
for(j=0;j<7;j++)
sum=sum+sales[4][j];
The indexing in an array always starts from zero, therefore, to calculate the sum of the fifth row, the user has to write 4 in the index to point to the fifth row.
The answer is performing arithmetic and logical operations
Since java.util.PriorityQueue doesn't use the Cloneable interface, I think it's safe to say that Serializable interfaces are implemented in all instances.