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sammy [17]
3 years ago
11

Laura is photographing her son’s baseball game. What ISO setting should she use?

Computers and Technology
1 answer:
zmey [24]3 years ago
7 0

Answer:

C High

Use a fast ISO setting on a digital camera when taking baseball photos, often professional photographer for baseball need to shoot with extremely high ISOs such as 1600, 3200, even 6400.

Explanation:

Professional sports photographers use shutter speed 1/1000 of a second to stop motion. and on today's camera that had the use of the perception of excess noise on cameras, which means noise has been virtually eliminated from today's cameras, so you'll get best result with higher ISO setting.

Learn More:

If you’re interested in learning more about photographs we recommend you to also take a look at

How are 3D photographs taken brainly.com/question/2879609

#LearnWithBrainly

You might be interested in
How to write a function that counts the letters in a string in C?
stiv31 [10]

Answer:

Here is the C function that counts the letters in a string:

int LetterCount(char string[]){  //function to count letters in a string passed as parameter

 string[100];  // char type string with size 100

  int i, letters;  // letter variable stores the count for no. of letters in string

   i = letters = 0;  //initialize variables i and letters to 0

  while (string[i] != '\0')  { // loop iterates through the entire string until end of string is reached

    if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  { // if condition checks the letters in the string

     letters++;    }  // increments 1 to the count of letters variable each time a letter is found in the string

    i++;  }  //increments value of i to move one character forward in string

   printf("Number of Letters in this String = %d", letters);   // displays the number of letters in the string

   return 0; }                              

Explanation:

Here the question means that the function should count the letters in a string. So the letters are the alphabets from a to z and A to Z.

Here is the complete program:

#include <stdio.h>   // to use input output functions

int LetterCount(char string[]){  // method that takes a character string as parameter and counts the letters in the string

string[100];  

int i, letters;

i = letters = 0;

while (string[i] != '\0')   {

 if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z'))

   {letters++;  }

   i++; }

   printf("Number of Alphabets in this String = %d", letters);  

   return 0;}  

int main(){  // start of main function

  char string[100];  //declares a char array of string

   printf("Please Enter a String : ");   //prompts user to enter a string

  fgets(string,100,stdin);  //get the input string from user

   LetterCount(string); } // calls method to count letters in input string

I will explain this function with an example

Lets suppose the user input "abc3" string

string[100] = "abc3"

Now the function has a while loop that while (string[i] != '\0')  that checks if string character at i-th position is not '\0' which represents the end of the character string. As value of i = 0 so this means i is positioned at the first character of array i.e. 'a'

At first iteration:

i = 0

letter = 0

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )   if condition checks if the character at i-th position of string is a letter. As the character at 0-th position of string is 'a' which is a letter so this condition evaluates to true. So the statement letter++ inside if condition executes which increments the letter variable to 1. So the value of letter becomes 1. Next statement i++ increments the value of i to 1. So i becomes 1. Hence:

i = 1

letter = 1

At second iteration:

i = 1

letter = 1

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 1st position of string is 'b' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:

i = 2

letter = 2

At third iteration:

i = 2

letter = 2

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 2nd position of string is 'c' which is a letter so this condition evaluates to true. So the statements letter++ inside if condition and i++ executes which increments these variables to 1. Hence:

i = 3

letter = 3

At fourth iteration:

i = 3

letter = 3

if( (string[i] >= 'a' && string[i] <= 'z') || (string[i] >= 'A' && string[i] <= 'Z') )  

if condition checks if the character at i-th position of string is a letter. As the character at 3rd position of string is '3' which is not a letter but a digit so this condition evaluates to false. So the statement letter++ inside if condition does not execute. Now i++ executes which increments this variable to 1. Hence:

i = 4

letter = 3

Now the loop breaks because while (string[i] != '\0') condition valuates to false as it reaches the end of the string.

So the statement: printf("\n Number of Letters in this String = %d", letters); executes which prints the value of letters on the output screen. Hence the output is:

Number of Letters in this String = 3

3 0
3 years ago
Tgif
VMariaS [17]
Science and mathematics. STEM can also be engineering but in John’s case, he’s a METEOROLOGIST WHO DOES THE WEATHER FORECAST and meteorologists is part of a study in science and also mathematics because of measuring the speed of some related computations
6 0
2 years ago
It takes an older computer twice as long to send out a company's email as it does a newer computer. Working together, it takes t
bulgar [2K]

Answer:

13,33  MIN.

Explanation:

1. Time with Older Computer (OC) = 2 time with New Computer (NC)

2. OC+ NC = 10 MIN.

replacing 1. in 2.    OC + OC/2 = 10 min.  

1.5 OC =10min

OC=6.66 MIN

NC = 3,33 MIN.

If we replace NC with OC , 3,33 min will take 2 times (6,66 min)

Total Time = 6,66 + 6,66= 13,33 min

4 0
3 years ago
A network administrator has been creating a baseline of network performance. During this process, he realizes that one router is
LiRa [457]

If the network administrator found that one of his routers is slow in performance better to check the traffic packet transactions. If any huge file size is been transferred better to disconnect the router and reconnect.

Possible to kill the network task packet so the network speed can be restored.

<u>Explanation:</u>

Moreover, possible to scan the end-user PC or workstation or desktop whether any malware or spyware is affected, if so better to remove that particular PC or workstation or desktop to disconnected from the router.

Updating the PC or workstation or desktop OS patches to be done at regular intervals.

5 0
3 years ago
If your computer determines the destination address of a network packet is to a remote network.
Arisa [49]

The data link layer software would replace the MAC address of the next hop or gateway when the destination address of a network packet is to a remote network.

<h3>What is a data link layer?</h3>

The data link layer is the second layer of the OSI model and it can be defined as an interface between the network and physical layer. Also, it comprises two (2) main sublayers and these include the following:

  • Logical link control (LLC) layer.
  • Media access control (MAC) layer.

In Computer networking, the data link layer software would replace the MAC address of the next hop or gateway when the destination address of a network packet is to a remote network.

Read more on data link layer here: brainly.com/question/13131540

#SPJ1

5 0
2 years ago
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