Let the weight of triangle be x units. You are given that the weight of square is 1 unit.
1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.
2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.
3) If the whole system is balanced, then the weights on left and right sides are equal:
3x+5=2x+7.
Solve this equation:
3x-2x=7-5,
x=2 units.
Answer: option A
Answer:
x = 20
Step-by-step explanation:
given a line parallel to a side of a triangle and intersecting the other two sides, then it divides those sides proportionally , that is
=
=
( cross- multiply )
5x + 10 = 110 ( subtract 10 from both sides )
5x = 100 ( divide both sides by 5 )
x = 20