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Ira Lisetskai [31]
3 years ago
12

Duncan earned $22 in interest. If his investment paid 2.5% and he invested his money for 6 months, how much money did he origina

lly invest?
Show work please
Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

For one month:22*.025=.55

For 6 moths: 6*.55 =3.3

The answer is 3.3 $

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

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3 years ago
Which table represents a linear function?<br> PLEASE HELP ME
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Answer:

Bottom left

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3 years ago
In 2000, the population of Big Springs was 13 thousand. Use the given doubling
trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is  t =0.

Formula:

A= A_0e^{rt}

Where,

A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year

for doubling time,

r = \frac{log (2)}{t} \\

r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007

Given value:

A = A_0e^{rt} \\\\

A_0 = 13000

t= 40 \ years

when year is 2000, t=0 so, year is 2100 year as t = 100.

A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4

7 0
3 years ago
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