Robert Hooke is the answer.
Glucose is the preferable source of energy for E. coli cells. By adding small amounts of glucose, 0.05% in this case, it would enable cell growth to proceed as usual until it has reached mid log growth phase. At this point, the small amount of glucose added should have been depleted and the E.coli cell will now be dependent on lactose present as its source of nutrients. Lactose will also inactivate lac repressors and given the lack of glucose, CAP binding to high amounts of cAMP will be activated and increase expression of lac operon genes.
It should be noted that this system of expression may not tightly regulate the expression of lac operon before the E.Coli reaches exponential phase. As lactose is still present, lac repressors will be inactivated throughout the entire experiment and hence small amounts of proteins might be produced even when not auto-induced. After auto-induction, CAP-cAMP protein complex will simply upregulate expression of lac operon genes.
<span>It's like incomplete dominance, but instead of one allele not being completely dominant for a trait, both alleles for that specific trait are dominant.</span>
Answer:
Effects of changing substrate concentration of hydrogen (2%, 2.5% and 3%) on enzymatic activity of catalase in dried yeast.
Explanation:
However, this hypothesis did explain the stabilization of the enzyme and hence the induced fit collisions kept on occurring making the reaction rate increase.
The correct answer is "applying cold compresses to the affected area".
Most of the people stang by a bee or wasp experience a localized reaction and only 3% of the people will exhibit an allergic reaction. The normal localized reaction includes reddening and swelling of the skin, along with a local itching and pain.
Although these reactions will probably start disappearing within a few hours, there are several things that the person could do to alleviate the pain and discomfort. The most important thing to do is to apply ice or cold compresses to the affected area, to reduce the body's inflammatory response.
