The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1
<h3>How to determine recursive formula of a geometric sequence?</h3>
Given: 1, 5, 25, 125, 625, ...
= 5
an = a × r^(n - 1)
= 1 × 5^(n - 1)
an = (1) × (5)^(n - 1) for n ≥ 1
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To solve for A, multiply each side by 9A to get rid of the fraction, so then 3 = 81(9A) --> 3 = 729A --> 3/729 = 1/243
16/3= 5 and 1/3
16* 5 and 1/3
=3, so 3 are not baseball players ,which means that 13 are
answer:13
Answer:
f = 2
Step-by-step explanation:
To get f on one side of the equal sign and the constant terms on the other side, you can add (2.75f-2) to both sides of the equation:
4f = 8
Dividing by the coefficient of f gives the desired result.
f = 2
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<em>Check</em>
2 +1.25(2) = 10 -2.75(2)
2 +2.50 = 10 -5.50
4.50 = 4.50 . . . . the answer checks OK
Answer
Volume for math practice?
Step-by-step explanation: