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3 years ago

10

ILL GIVE BRAINLIEST! PLEASE ANSWER IF YOU SEE THIS!!! David has a container filled with quarters and nickels. He has 29 coins wh

ich add up to $5.85. How many quarters does he have?

2 answers:

masha68 [24]3 years ago

5 0

22 quarters and 7 nickels

Vilka [71]3 years ago

3 0

David has 22 quarters and 7 nickels.

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a grocery store sells 6-pack of bottled water for $3.79 a 9 pack for $4.50 and a 12 pack for $6.89 which package costs the least

DerKrebs [107]

Find the unit price (price per bottle)
$3.79 ÷ 6 = $.63 a bottle (approximately)
$4.50 ÷ 9 = $.50
$6.89 ÷ 12 = $.57 (approximately)

So your best bet is the 9 pack.
You will find that sometimes your best value is not to buy the greatest amount of a product.

4 0

3 years ago

Need help asap I’m stuck

qwelly [4]

Answer:

None

since the slopes are equal, it's either infinite or none.

since the ratios of Ys and Xs is 1, 18/16 should be 1 to say we have infinite answers. since it's not, the is no solution at all.

3 0

3 years ago

Read 2 more answers

Ill give brainiest for this question :D<br> (its not multiple choice)

Ipatiy [6.2K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{6c-2}{2}$ + 2c + 11

= $\frac{6c}{2}$ - $\frac{2}{2}$ + 2c + 11

= 3c - 1 + 2c + 11

= 5c + 10

(b)

We have the expression

5c + 10 ← factor out 5 from each term

= 5(c + 2)

6 0

3 years ago

. A car bought for $20,000. Its value depreciates by 10% each year for 3 years. What is the car's worth after3 years?

Mila [183]

Answer:

$14,580

Step-by-step explanation:

To start off, 10% of 20,000-one easy way to do this is to multiply 20,000 by 0.1, which is 10% in decimal form

-In doing that, you get 2,000

-Now the question says that the value is depreciated which means it goes down in value, so subtract 2,000 from 20,000 to 18,000

-the value of the car after one year is now $18,000

Now, let's move to the second year. This time find 10% of 18,000

-multiply 18,000 by 0.1 to get 1,800

-since the value is depreciating, or becoming less, we will subtract 1,800 from 18,000 to get 16,200

-the value of the car after two years is now $16,200

Finally, let's look at the value of the car after three years. Only this time, we will now find 10% of 16,200

-multiply 16,200 by 0.1 to get 1,620

-since value is being depreciated, or lessened, we will once again be subtracting. Subtract 1,620 from 16,200 to get 14,580

Therefore, the value of the car after three years is now $14,580.

4 0

3 years ago

Use the exponent properties to simplify the following <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283x%5E2%29%5E3%7D%7B%28

IrinaK [193]

Answer:

$\dfrac{27}{16}x^2$

Step-by-step explanation:

The relevant properties are ...

(a^b)^c = a^(bc)

(a^b)/(a^c) = a^(b-c)

So, the expression simplifies to ...

$\dfrac{(3x^2)^3}{(2x)^4}=\dfrac{3^3x^{2\cdot 3}}{2^4x^4}=\dfrac{27}{16}x^{6-4}=\dfrac{27}{16}x^{2}$

6 0

4 years ago