Find the perimeter of the figure. SOMEONE PLS HELP ME IVE ASKED THIS QUESTION 3 TIMES NOW
1 answer:
Answer:
Step-by-step explanation:
The lengths of the tangents drawn from an external point tot he circle are equal.
RA = RB = 12.2
QA = QC = 5.9
PC = PQ - QC = 27.4 - 5.9 = 21.5
PC = PB = 21.5
QR = QA + RA = 5.9 + 12.2 = 18.1
PR = PB + RB = 21.5 + 12.2 = 33.7
Perimeter = PQ + QR + PR
= 27.4 + 18.1 + 33.7
= 79.2
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Answer:
<h3>The 12th term is 1771470</h3>Step-by-step explanation:
Since the above sequence is a geometric sequence
An nth term of a geometric sequence is given by
where a is the first term
r is the common ratio
n is the number of terms
From the question
a = 10
To find the common ratio divide the previous term by the next term
That's
r = 30/10 = 3 or 90/30 = 3 or 270/90 = 3
Since we are finding the 12th term
n = 12
So the 12th term is
Hope this helps you