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lora16 [44]
2 years ago
10

For each pair of functions F and G below, find f(g(x)) and g(f(x)).

Mathematics
1 answer:
8090 [49]2 years ago
8 0

Answer:

FG

Step-by-step explanation:

COOL AIDS BRO FAX AND MORE STUFF

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If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in
pantera1 [17]

Answer:

v=9i+3j

Step-by-step explanation:

The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).

The vector v is found by subtraction the initial point from the terminal point.

v=<4,1>-<-5,-2>

v=<4--5,1--2>

v=<9,3>

We write v as multiples of the basis vectors to obtain:

v=9i+3j

8 0
3 years ago
What is the solution to the inequality 1/5x-4&lt;-2/5x​
timurjin [86]

Answer:

I'm sure the answer to this is: x<20/3

6 0
2 years ago
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Which statement is correct when a scatterplot is constructed? A.The independent variable is the input variable and should be rep
spayn [35]

Answer:-  A.The independent variable is the input variable and should be represented by the x-axis.


Explanation:-

A. Correct.

B. Not correct.

<u>Reason</u>:- The independent variable is the input variable and should be represented by the x-axis.

C. Not correct.

<u>Reason</u>:- The dependent variable is the output variable and should be represented by y-axis.

D. Not correct.

<u>Reason</u>:-The dependent variable is the output variable and should be represented by y-axis.


6 0
2 years ago
Is {(2,4)(3, 4). (4,4), (5, 6)} a relation?*
kirill115 [55]

Yes I hope it helps and sorry if it’s wrong
7 0
2 years ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

           x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
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