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e-lub [12.9K]
3 years ago
12

How do you create a restriction for √z + 8=13 ?

Mathematics
2 answers:
Zinaida [17]3 years ago
6 0
√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)
igor_vitrenko [27]3 years ago
4 0

I found this on the internet I hope it helps

√z = 13 - 8
√z = 5
z = 5²
z = 25

its on the answer key xD

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Alecsey [184]

Solution,6b+7-2b=1+5b\quad :\quad b=6

Steps:

6b+7-2b=1+5b

\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b

\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7

\mathrm{Simplify}, 4b=5b-6

\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b

\mathrm{Simplify}, -b=-6

\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}

\mathrm{Simplify}, b=6

\mathrm{The\:Correct\:Answer\:is\:b=6}

\mathrm{Hope\:This\:Helps!!!}

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3 0
3 years ago
Read 2 more answers
Help please! Thank you! :D❤️
MissTica
I believe it is GCF because 9v^3 can be factored out of the expression, becoming:
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Answer:

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Step-by-step explanation:

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Since 56/56 employees at the sports shop work part time, that means 100% of them do, or all of them.

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