Answer: You can see it does matter in what order you solve the equation. ... Just like when you are solving equations with whole numbers, solving equations with fractions has the same order of operations. The order of operations is the order in which you solve the problem. If numbers are in parentheses, you do them first.
Answer:
The best estimate for the average temperature in October at 10 a.m. is 73.8 degrees Fahrenheit.
Solution:
Number of hours after 5 a.m.: x
At 10 a.m.→x=10-5→x=5
yˆ=−0.37(5)^2+6.15(5)+52.3
yˆ=−0.37(25)+30.75+52.3
yˆ=−9.25+30.75+52.3
yˆ=73.8
Answer: The best estimate for the average temperature in October at 10 a.m. is 73.8 degrees Fahrenheit.
Answer:
Step-by-step explanation:
L = Length
W = Width
W = 2L
2W + 2L = 174
2(2L) + 2L = 174
6L = 174
L = 29 ft
W = 2(29) = 58 ft
The <em>approximate surface</em> areas of corresponding prisms are listed below:
- <em>A = 108 units²</em>
- <em>A = 229 units²</em>
- <em>A = 454 units²</em>
<h3>How to match given surface areas with given figures</h3>
The <em>surface</em> area of the each figure (
), in square units, is equal to the sum of the <em>surface</em> area of the two bases (
), in square units, and the <em>surface</em> areas of the <em>lateral</em> sides (
), in square units. Since bases are <em>regular</em> polygons, <em>base surface</em> area can be determined by this expression:
(1)
Where:
- <em>l</em> - Side length, in units
- <em>n</em> - Number of sides
The area of one lateral side is expressed by this expression:
(2)
Where <em>h</em> is the height of the rectangle, in units.
The total surface area is defined by the following formula:
(3)
Now we proceed to calculate each surface area:
<h3>Case I (
,
,
)</h3>
![A = 2\cdot \left[\frac{2^{2}\cdot (6)}{4\cdot \tan \left(\frac{180}{6} \right)} \right]+6\cdot (2)\cdot (9)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cleft%5B%5Cfrac%7B2%5E%7B2%7D%5Ccdot%20%286%29%7D%7B4%5Ccdot%20%5Ctan%20%5Cleft%28%5Cfrac%7B180%7D%7B6%7D%20%5Cright%29%7D%20%5Cright%5D%2B6%5Ccdot%20%282%29%5Ccdot%20%289%29)
<em>A = 108.136 units²</em>
<h3>Case II (
,
,
)</h3>
![A = 2\cdot \left[\frac{(4\sqrt{3})^{2}\cdot (3)}{4\cdot \tan \left(\frac{180}{3} \right)} \right]+3\cdot (4\sqrt{3})\cdot (9)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cleft%5B%5Cfrac%7B%284%5Csqrt%7B3%7D%29%5E%7B2%7D%5Ccdot%20%283%29%7D%7B4%5Ccdot%20%5Ctan%20%5Cleft%28%5Cfrac%7B180%7D%7B3%7D%20%5Cright%29%7D%20%5Cright%5D%2B3%5Ccdot%20%284%5Csqrt%7B3%7D%29%5Ccdot%20%289%29)
<em>A = 228.631 units²</em>
<h3>Case III (
,
,
)</h3>
![A = 2\cdot \left[\frac{6^{2}\cdot (5)}{4\cdot \tan \left(\frac{180}{5} \right)} \right]+5\cdot (6)\cdot (11)](https://tex.z-dn.net/?f=A%20%3D%202%5Ccdot%20%5Cleft%5B%5Cfrac%7B6%5E%7B2%7D%5Ccdot%20%285%29%7D%7B4%5Ccdot%20%5Ctan%20%5Cleft%28%5Cfrac%7B180%7D%7B5%7D%20%5Cright%29%7D%20%5Cright%5D%2B5%5Ccdot%20%286%29%5Ccdot%20%2811%29)
<em>A = 453.874 units²</em>
The <em>approximate surface</em> areas of corresponding prisms are listed below:
- <em>A = 108 units²</em>
- <em>A = 229 units²</em>
- <em>A = 454 units²</em>
To learn more on surface areas, we kindly invite to check this verified question: brainly.com/question/2835293
