The space shuttle travels at 28000 mph while orbiting the earth. How far does the shuttle travel in feet per day

Mathematics

1 answer:

STatiana [176]3 years ago

6 0

We are given the speed of the shuttle as:

speed = 28,000 miles / hour

We know that:

1 mile = 5280 ft

24 hour = 1 day

Therefore by conversion:

speed = (28,000 miles / hr) * (5280 ft / 1 mile) * (24 hr / day)

speed = 3,548,160,000 ft / day

In 2 significant figures:

speed = 3.5 x 10^9 ft / day

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What does it mean if a statistic is resistant? choose the correct answer below.

matrenka [14]

When we say a statistic is resistant, we mean the extreme values do not affect the statistic to a large extent or to an extent which makes a major difference. Mean and median are example of such statistics. By changing the extreme values we do not see a substantial difference in the value of mean and median for the data set.

Consider a sample: 1,2,3,4,4,5,6,7,8
The median for this data set is 4.
If we change the extreme values to get this sample: -5,2,3,4,4,5,6,7,100
The median will still be the same i.e. 4. This is what is meant by a resistant statistic.

So option a is the correct ans.

4 0

3 years ago

Hey can you please help! posted picture of question

frosja888 [35]

The solution of the system can be x - 3y = 4 only if both the equations can be simplified to x - 3y = 4.

This will mean that both the equations will result in the same line which is x - 3y = 4 and thus have infinitely many solutions.

Second equation is:

Qx - 6y = 8
Taking 2 common we get:

(Q/2)x - 3y = 4

Comparing this equation to x- 3y = 4, we can say that

Q/2 = 1
So,
Q = 2

Therefore, the second equation will be:

2x - 6y = 8

5 0

3 years ago

given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0

jonny [76]

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx$
$\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx$
$\implies \dfrac12y^2=x^3+2x^2+C$

When $x=1$ you have $y=\sqrt{10}$ , so

$\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2$

and so the particular solution to the ODE is

$\dfrac12y^2=x^3+2x^2+2$

Then when $x=0$ , you get

$\dfrac12y^2=0^3+2(0)^2+2=2$
$\implies y^2=4$
$\implies y=2$

where we omitted the negative root because it's given that $y>0$ .