i don’t know but you could prob use photo math. that would hell
<em>2 solutions</em>
<em>X= 16</em>
<em>X=49</em>
Step-by-step explanation:
<em>original equation</em>
<em>x-11√x+28 = 0</em>
<em> Isolate</em>
<em> -11√x = -x-28+0</em>
<em> Tidy up</em>
<em> 11√x = x+28</em>
<em> Raise both sides to the second power</em>
<em> (11√x)2 = (x+28)2</em>
<em>After squaring</em>
<em> 121x = x2+56x+784</em>
<em> Plug in 49 for x </em>
<em> 11√(49) = (49)+28</em>
<em>Simplify</em>
<em> 11√49 = 77</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 49
<em>Plug in 16 for x </em>
<em> 11√(16) = (16)+28</em>
<em>Simplify</em>
<em> 11√16 = 44</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 16
Study all notes, reread the chapters again. Have someone ask questions on the chapters page by page. This always has worked for me. Plus try to do this again the night before the test. You will be surprised how much you can remember by doing it again the night before the test. Hope this helps.
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
Answer:
17
Step-by-step explanation:
f(5)=3*5+2 where X is equal to 5
