The translation of the given figure will have vertices, A'(1,2), B'(3,2), C'(3,-5), and D(-1,-3) from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

In the question, we are asked to translate the given figure 2 units left and 7 units down.

In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.

For any point P(x, y) the given rule says that after translation,

P(x, y) becomes P'(x - 2, y - 7).

The coordinates of the given figure are:

A(3,9), B(5,9), C(5,2), and D(1,4).

After translation, these points can be shown as:

A(3,9) becomes A'(1,2).

B(5,9) becomes B'(3,2).

C(5,2) becomes C'(3,-5).

D(1,4) becomes D'(-1,-3).

Thus, the translation of the given figure will have vertices, A'(1,2), B'(3,2), C'(3,-5), and D(-1,-3) from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

Learn more about translations at

brainly.com/question/1400185

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7 0

2 years ago

HELPPP?!!! What is the value of f(-2) and f(3)

Cerrena [4.2K]

Step #1 for both: figure out which interval your x-value fits into.
For f(-2), x=-2 and -2 fits with x ≤ -2, the top interval.
For f(3), x=3 and 3 fits into -2 < x ≤ 3, the middle interval.

Step #2 for both, plug in your x-value to the piece of the function that fits with that interval.
For f(-2), we know x≤-2, so we use 2x+8 to evaluate x=-2.
For f(3), we know -2
f(-2) = 2(-2)+8 = -4+8 = 4

f(3) = (3)^2 -3 = 9-3 = 6

3 0

3 years ago

If 4(r+2)-13=11, what is the value of r ?

vichka [17]

Answer:

r=4

Step-by-step explanation:

First you multiply 4 by r which gives you 4r. Then you multiply 4 by 2 to give you 8.So it looks like this now

4r+8-13=11

Now you add thirteen to both sides and get

4r+8= 24

Then you subtract both sides by 8 to get 16

4r=16

Then you divide both sides by 4 to get 4

r=4

3 0

3 years ago