Answer:
x= 36 and y= 9
Step-by-step explanation:
because I said so. jk math
Joshua used commutative property to rewrite the expression.
Hey there! I'm happy to help!
We want to find to find the length of the wire that will go around the friends field. The distance around something is called the perimeter. To find this, we will take our two sides with the length of 219 and two sides with the width of 7525 and then add them.
2(219)+2(7525)=15488
Therefore, we will need a wire with a length of 15488.
I hope that this helps! Have a wonderful day!
Answer:
Option 1.
The limit does not exist.
Step-by-step explanation:
The function is
![f(x) = \left \{{{x+3\ \ \ if\ \ \ x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cleft%20%5C%7B%7B%7Bx%2B3%5C%20%5C%20%5C%20if%5C%20%5C%20%5C%20x%3C2%7D%20%5Catop%7B3-x%5C%20%5C%20%5C%20%5C%20if%5C%20%5C%20%5C%20x%5Cgeq2%7D%7D%20%5Cright.)
We seek to find
![\lim_{x \to 2}f(x)](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%202%7Df%28x%29)
Then we must find the limits on the right of 2 (
) and on the left of 2 (
)
If both limits exist and are equal then the
exists, if both limits are different or do not exist then the
does not exist.
<u><em>Limit on the left of 2</em></u>
![\lim_{x \to 2^-}x+3 = (2) +3 =5\\\\ \lim_{x \to 2^-}x+3 =5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%202%5E-%7Dx%2B3%20%3D%20%282%29%20%2B3%20%3D5%5C%5C%5C%5C%20%5Clim_%7Bx%20%5Cto%202%5E-%7Dx%2B3%20%3D5)
<u><em>Limit on the rigth of 2</em></u>
![\lim_{x \to 2^+}3-x = 3-(2) = 1\\\\ \lim_{x \to 2^+}3-x =1](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%202%5E%2B%7D3-x%20%3D%203-%282%29%20%3D%201%5C%5C%5C%5C%20%5Clim_%7Bx%20%5Cto%202%5E%2B%7D3-x%20%3D1)
Note that both limits give different results. The limit of f(x) when x tends to 2 on the left is equal to 5, and the limit of f(x) when x tends to 2 on the rigth is equal to 1.
Then the
does not exist.