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zalisa [80]
4 years ago
13

Is (-1,2) a solution of the system y>x and x+y=>

Mathematics
1 answer:
valentina_108 [34]4 years ago
8 0
(-1,2) is a solution

y>x

2>-1 is correct

in this case yes

x+y≥x

 -1+2≥-1 

1≥-1 is correct: Yes

in this case no

x+y≥y

1≥2 

is not correct. No


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When the lines are parallel then there is no solution to the system of equations.
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3 0
3 years ago
Mr. Gurung sold a bicycle for Rs 18,816 and made a profit of 12%. if he wants
LenaWriter [7]

Answer:

Rs. 23520

Step-by-step explanation:

Given that :

At 12% profit ; sales price = 18,816

At (12 + 3)% profit ; sales price = x

Hence,

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0.15 = x

Cross multiply ;

0.12x = 0.15 * 18816

0.12x = 2822.4

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5 0
3 years ago
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Korvikt [17]
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4 0
3 years ago
Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]
madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

3 0
2 years ago
Read 2 more answers
6p+2+ p - 3 = 8p - 8​
saul85 [17]
6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7
7 0
3 years ago
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