PLEASE HELPPP! ILL GIVE 50 POINTS ACTUALLY PUT THE ANSWER PLEASE ..
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
The equation of a circle in the general form is:
The equaton of a circle in standard form is:
Where the center is at <em>(h, k)</em> and <em>r</em> is the radius
To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:
1- Given the equation in general form:
2- Complete the square:
-Group the like terms and move the constant to the other side.
- Complete the square on the left side of the equation.
- Add the same value to the other side.
Then you obtain:
Answer:
B) \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Step-by-step explanation:
Step 1: First we have to get rid off the roots in the denominator.
To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.
The conjugate of √5 + √3 is √5 - √3.
Now multiply given expression with √5 - √3
(√6 + √11) (√5 - √3)
------------- x -----------
(√5 + √3) (√5 - √3)
Step 2: Multiply the numerators and the denominators.
√6√5 - √6√3 +√11√5 -√11√3
------------------------------------------
(√5)^2 - (√3)^2
Now let's simplify to get the answer.
√30-√18 +√55 - √33
-----------------------------
5 - 3
= √30 -3√2 +√55 [√18 = √9√2 = 3√2]
--------------------------
2
The answer is \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Thank you.