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4 years ago

I need an answer to this question

Mathematics

1 answer:

solmaris [256]4 years ago

8 0

Let me try it now and l will give u the response

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A line has a slope of -5/8. What is the slope of the line parallel to it; and what is the slope of the line perpendicular to it?

Andrei [34K]

To find the slope of the line parallel to it, all you have to do is change the y-intercept, or the b in y = mx + b...

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3 years ago

Desmond wants to sell his car that he paid $8,000 for 2 years ago. The car depreciated, or decreased in value, at a constant rat

alukav5142 [94]

Answer:

8,000 - 24x

Step-by-step explanation:

Let

y ----> depreciated value of the car

x---> rate of depreciation

t ----> the time in months

we know that

The linear equation that represent this situation is

y=8,000-xt

For t=2 years=2*12=24 months

substitute

y=8,,000-x(24)

y=8,000-24x

6 0

4 years ago

Read 2 more answers

Identify the hypothesis of the statement If x + 4 = 5, then x = 1.

Cerrena [4.2K]

Answer:

hypothesis is an educated guess. it follows the word if in If, then statements.

following the word then is your conclusion

6 0

3 years ago

Find the constant of variation for the relation and use it to write and solve the equation.

Ksenya-84 [330]

Answer:

When x = 1 and z = 4, $y=\frac{80}{9}$

Step-by-step explanation:

The variation described in the problem can be written using a constant of proportionality "b" as:

$y=b\,\,x\,\,z^2$

The other piece of information is that when x = 5 and z = 1, then y gives 25/9. So we use this info to find the constant "b":

$y=b\,\,x\,\,z^2\\\frac{25}{9} =b\,\,(5)\,\,(1)^2\\\frac{25}{9} =b\,\,(5)\\b=\frac{5}{9}$

Knowing this constant, we can find the value of y when x=1 and z=4 as:

$y=b\,\,x\,\,z^2\\y=\frac{5}{9} \,\,x\,\,z^2\\y=\frac{5}{9} \,\,(1)\,\,(4)^2\\y=\frac{5*16}{9}\\y=\frac{80}{9}$

3 0

3 years ago

Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.

expeople1 [14]

Rewriting the two equations:

[Supply] $p = q^2+20$
[Demand] $p=-4q^2+10q+18600$

Equilibrium price is when
Supply = Demand
$q^2+20 = -4q^2+10q+18600$
$q^2+4q^2+20-10q-18600 = 0$
$5q^2-10q-18580=0$ ⇒ Simplifying the equation by dividing each term by 5

$q^2-2q-3716=0$

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula.

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation.
$q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}$ , and $q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}$

We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
$q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97$
$q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97$

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62

4 0

3 years ago