The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
<h3>What is the range of a quadratic equation?</h3>
In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.
x = - 9
y = (2 / 3) · (- 9)² - 6
y = 48
x = - 6
y = (2 / 3) · (- 6)² - 6
y = 18
x = - 3
y = (2 / 3) · (- 3)² - 6
y = 0
x = 0
y = (2 / 3) · 0² - 6
y = - 6
x = 3
y = (2 / 3) · 3² - 6
y = 0
x = 6
y = (2 / 3) · 6² - 6
y = 18
x = 9
y = (2 / 3) · 9² - 6
y = 48
The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.
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For 1 kilometer, the customary measure is 62/100 miles. The easiest way to think about this is to forget that the units are miles. Instead think of it as money. If I have $1 that means I have 100 out of 100 cents. So if I have 50 cents my fraction is 50/100; and the way we write this is 0.50... if I have 32 cents then my fraction is 32/100 and we write this as 0.32. So if you have 62 cents out of a 100, how would you write that in decimal form?
Answer:
1/5
Step-by-step explanation:
The number 5 or greater than 4 is 5.
1 number out of 5 total parts.
= 1/5
P(5 or greater than 4) = 1/5
Complementary angles add up to 90°
Let the unknown angle be 0..
0 + 42 = 90°
0= 90° - 42° = 48°
therefore, The complimentary angle of
42 is 48°
