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Alika [10]
3 years ago
11

2x+3y= 143х - 4 y = 4​

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0

The solution to given system of equations are (x, y) = (4, 2)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 14 ---------- eqn 1

3x - 4y = 4 --------- eqn 2

We have to solve the given system of equations

We can solve the above system of equations by elimination method

<em><u>Multiply eqn 1 by 3</u></em>

3(2x + 3y = 14)

6x + 9y = 42 --------- eqn 3

<em><u>Multiply eqn 2 by 2</u></em>

2(3x - 4y = 4)

6x - 8y = 8 ----------- eqn 4

<em><u>Subtract eqn 4 from eqn 3</u></em>

6x + 9y = 42

6x - 8y = 8

( - ) --------------

9y + 8y = 42 - 8

17y = 34

<h3>y = 2</h3>

<em><u>Substitute y = 2 in eqn 1</u></em>

2x + 3(2) = 14

2x + 6 = 14

2x = 14 - 6

2x = 8

<h3>x = 4</h3>

Thus the solution to given system of equations are (x, y) = (4, 2)

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Step-by-step explanation:

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The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.

Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.

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<h3>What is the solution?</h3>

Let us recall that what we have here is a radical equation as follows;

√7x+1 - √x-5 = 6

When we isolate we have';

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