2x+3y= 143х - 4 y = 4

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

The solution to given system of equations are (x, y) = (4, 2)

Solution:

Given system of equations are:

2x + 3y = 14 ---------- eqn 1

3x - 4y = 4 --------- eqn 2

We have to solve the given system of equations

We can solve the above system of equations by elimination method

Multiply eqn 1 by 3

3(2x + 3y = 14)

6x + 9y = 42 --------- eqn 3

Multiply eqn 2 by 2

2(3x - 4y = 4)

6x - 8y = 8 ----------- eqn 4

Subtract eqn 4 from eqn 3

6x + 9y = 42

6x - 8y = 8

( - ) --------------

9y + 8y = 42 - 8

17y = 34

Substitute y = 2 in eqn 1

2x + 3(2) = 14

2x + 6 = 14

2x = 14 - 6

2x = 8

Thus the solution to given system of equations are (x, y) = (4, 2)

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