3 years ago

Help it’s for today, not accepting links

Chemistry

1 answer:

Kamila [148]3 years ago

7 0

Answer:

Percent composition by mulecules is: (mass of element/molecular mass) x 100

Percent composition by atoms is: (mass of element/molecular mass) x 100.

Explanation:

So their the same

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g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g)

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Answer: At equilibrium , there are 0.274 moles of $Br_2$

Explanation:

Moles of $H_2$ = 0.682 mole

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The given balanced equilibrium reaction is,

$H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)$

Initial conc. 0.341 M 0.220 M 0 M

At eqm. conc. (0.341-x) M (0.220-x) M (2x) M

Given : (0.341-x) M = 0.258 M

x= 0.083 M

Thus equilibrium concentartion of $Br_2$ = (0.220-0.083) M = 0.137 M

Thus moles of $Br_2$ at equilibrium = $0.137M\times 2.00L=0.274mol$

At equilibrium , there are 0.274 moles of $Br_2$

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