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ss7ja [257]
3 years ago
9

HELP QUICK ILL MARK BRAINLIEST

Chemistry
2 answers:
Rzqust [24]3 years ago
5 0

Answer:

When the ice cubes is left on a counter, it will melt as the forces that make its molecules stick together is broken. If that tray is put back in the freezer again, the water will freeze into cubes again.

Explanation:

lbvjy [14]3 years ago
3 0

Answer:

D) The water will freeze into cubes again.

Explanation:

When the ice cubes is left on a counter, it will melt as the forces that make its molecules stick together is broken.

If that tray is put back in the freezer again, the water will freeze into cubes again.

When water freezes, the molecules slow down and settle into its place, arranging in a regular shape that can be appeared as crystals (ice cubes).

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What is the term for the number of protons in the nucleus of each atom of an element?
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Answer:

atomic number

Explanation:

atomic number is the number of protons

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1 year ago
Write the difference between isomerism and allotropy with one example each.
fredd [130]

Answer:

hope it helps ..

Explanation:

Allotropes can be defined as different types of compounds made out of the same single element but in different chemical formulas and different arrangements. Isomers can be defined as the chemical compounds that have a similar molecular formula but with different structural formulae. Graphite and Diamond.

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2 years ago
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3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

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