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3 years ago

HELP QUICK ILL MARK BRAINLIEST

Chemistry

2 answers:

Rzqust [24]3 years ago

5 0

Answer:

When the ice cubes is left on a counter, it will melt as the forces that make its molecules stick together is broken. If that tray is put back in the freezer again, the water will freeze into cubes again.

Explanation:

lbvjy [14]3 years ago

3 0

Answer:

D) The water will freeze into cubes again.

Explanation:

When the ice cubes is left on a counter, it will melt as the forces that make its molecules stick together is broken.

If that tray is put back in the freezer again, the water will freeze into cubes again.

When water freezes, the molecules slow down and settle into its place, arranging in a regular shape that can be appeared as crystals (ice cubes).

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The high electrical conductivity of metals is primarily due to

zubka84 [21]

High conductivity of metals is caused by electrons that are free to move through the lattice.

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3 years ago

Can anyone here help me with chemistry

Kay [80]

The answer is 20g N2

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3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

5 0

3 years ago

Changes in which two characteristics can indicate a physical change?

liberstina [14]

Answer:

A-Shape

C-state

Explanation:

reactivity and flammability are both indicators of chemicals changes

6 0

3 years ago

Read 2 more answers

A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul

ioda

Answer:

%age Yield = 85.36 %

Solution:

The Balance Chemical Reaction is as follow,

C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O

According to Equation ,

100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀

So,

4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀

Solving for X,

X = (4.0 g × 82 g) ÷ 100 g

X = 3.28 g of C₆H₁₀ (Theoretical Yield)

As we know,

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

%age Yield = (2.8 g ÷ 3.28 g) × 100

%age Yield = 85.36 %

5 0

3 years ago