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3 years ago

A rock has the density of 8g/ml. If the rocks mass is 2g what is the rocks volume ?

Chemistry

2 answers:

klemol [59]3 years ago

7 0

Answer:1/4 ml

Explanation:

Density=8g/ml

Mass=2g

Volume=mass/density

Volume=2/8

Volume=1/4 ml

Leviafan [203]3 years ago

5 0

Answer: Volume = 0.25 mL

Explanation: Density is expressed as mass of the object per unit volume. So derive for volume,

d = m/ V

Volume is expressed as mass divided by density or V = m /d

V = 2 g / 8 g /mL

= 0.25 mL

Cancel out the unit in grams and the remaining unit is in mL.

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The Haber reaction for the manufacture of ammonia is: N2 + 3H2 → 2NH3 Without doing any experiments, which of the following can

Dimas [21]

Answer : The correct statement is, $\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The expression for rate of reaction :

$\text{Rate of disappearance of }N_2=-\frac{d[N_2]}{dt}$

$\text{Rate of disappearance of }H_2=-\frac{1}{3}\frac{d[H_2]}{dt}$

$\text{Rate of formation of }NH_3=+\frac{1}{2}\frac{d[NH_3]}{dt}$

From this we conclude that,

$\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

Hence, the correct statement is, $\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

3 0

3 years ago

When can resonance structures be written for a molecule

Serga [27]

When there are pi bonds as well as the sigma bonds, and therefore a double or triple bond. When it can change where that double bond is you can draw a resonance structure. Ozone, O3, has two resonance structures because you can rearrange the bonds in it.

4 0

4 years ago

According to the Brensted-Lowry model write the equation for provided acid showing

Taya2010 [7]

Answer:

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Explanation:

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3 years ago

What is 21.97 to three significant figures

antiseptic1488 [7]

21.97

Sig Figs

Decimals

Scientific Notation

2.197 × 101

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

What is the ph of a 0.085 m solution of nitrous acid (hno2) that has a ka of 4.5 × 10-4?

True [87]

Data Given:
Molarity = 0.085 M

Ka = 4.5 × 10⁻⁴
To Find:
pH = ?
Solution:
First find out the concentration of [H⁺] Ions using following formula,

[H⁺] =   $\sqrt{Ka . M}$

Puting values,

[H⁺] =   $\sqrt{0.00045 * 0.085}$

[H⁺] =   $\sqrt{0.00003825}$

[H⁺] =  <span>0.00618465843
</span>Or,
[H⁺] = 6.18 × 10⁻³

Calculate pH as,

pH = -log [H⁺]

pH = -log (6.18 × 10⁻³)

pH = 2.20

3 0

4 years ago