Answer: b. Nutrients that leave the small intestine via blood are delivered first to the liver.
Explanation:
Lymph is a clear fluid that leeks out from the interstitial spaces of the cells and this comprises of electrolytes, blood proteins, and antibodies. It is pushed towards the heart from the lymphatic vessels. The nutrients from the small intestine are drained into the bloodstream and they are circulated to all parts of the body and not directly destined towards the liver.
Answer:
Ventral
Explanation:
This is because when you want to dissect a pig, it's back is place on a dissecting tray and it's belly side is up which is the ventral side. With the ventral side, dissection will be easy and the major organs and systems can be observed easily as they will be rightly viewed because they are obvious and rightly placed at belly side up.
Answer:
<u> The following four traits are -: </u>
- <u>Pedigree 1 -</u> A recessive trait (autosomal recessive) is expressed by pedigree 1.
- <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
- <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
- <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.
Explanation:
<u>Explaination of each pedigree chart</u>-
- Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected.
In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa) - <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (
) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical
must be contributed by II-6. - The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
- <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.
In the question the pedigree chart was missing ,hence it is given below.
Answer:
The answer is not in any of the options and is the following:
to eliminate any remaining Hfr cells.
Explanation:
In a medium that has a streptomycin antibiotic it is used to kill Hfr donor cells after the conjugation is interrupted. This is entirely due to the streptomycin sensitivity allele (str-s) which are found in Hfr strains. The presence of the streptomycin resistance allele, located in the receptor, is used for the specific destruction of Hfr donor cells after conjugation occurs.
It's Out Of C Or D Because It Explains It