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4 years ago

The distance a freely falling object falls from rest is one-half second is?

Physics

1 answer:

Schach [20]4 years ago

7 0

Answer:

$s = ut + \frac{1}{2}a {t}^{2} \\ = \frac{1}{2} \times 9.81 \times ({ \frac{1}{2} })^{2} \\ s = 1.22m$

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"A hiker starts at point P and walks 2.0 kilometers due east and then 1.4 kilometers due north. The vectors in the diagram below

Law Incorporation [45]

Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]

Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
x = 35 [ tan 35 = 0.70 ]

In short, Your Answer would be 35 degrees

Hope this helps!

3 0

3 years ago

The baseball diamond is a square with sides 27.4 m long. If the positive x-axis points from home plate to first base and the pos

miss Akunina [59]

Answer:

What is the magnitude of the player 's displacement? A baseball "diamond" is a square, each side of length 27.4 m, with home plate and if each length of the base is 27.4 m, and the baseball player ran to third base,Then, the baseball player is 27.4 feet away from home plate (where he started)below the horizontal.

Explanation:

5 0

3 years ago

Carbon-14 is used to determine the age of ancient objects. If a sample today contains 0.060 g of carbon-14, how much carbon-14 m

MakcuM [25]

Answer: 86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

Explanation:

Half-life of sample of carbon -14= 5,730 days

$\lambda=\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{5,730 days}=0.00012 day^{-1}$

Let the sample present 11,430 years(t) ago = $N_o$

Sample left till today ,N= 0.060 g

$N=N_o\times e^{-\lambda t}$

$ln[N]=ln[N]_o-\lambda t$

$\log[0.060 g]=\log[N_o]-2.303\times 0.00012 day^{-1}\times 11,430 days$

$\log[N_o]=1.9369$

$N_o=86.47 g$

86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

5 0

4 years ago

Read 2 more answers

You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of

artcher [175]

Answer:

The distance is 1.026 m.

Explanation:

mass of rod, M = 1.23 kg

Length, L = 1.25 m

mass, m = 10 kg

Time period, T = 2 s

Let the distance is d.

The formula of the time period is given by

$T = 2\pi\sqrt\frac{\frac{1}{3}ML^2+md^2}{(M +m)g}\\\\2\times 2 = 4\pi^2\times \frac{\frac{1}{3}\times1.23\times1.25\times 1.25+ 10d^2}{(1.23 + 10)\times9.8}\\\\11.16 = 0.64 + 10d^2\\\\d= 1.026 m$

3 0

3 years ago

Read the scenario below and answer the question that follows.

IceJOKER [234]

I think it is a because she cries when she sees them

5 0

3 years ago