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2 years ago

How to do this question

Physics

1 answer:

mestny [16]2 years ago

4 0

thanks again and have to go to the store and get some rest I will be there at puno my phone is not working and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about the week and I have a few questions about you

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NEED HELP ASAP PLEASE!

katrin [286]

Answer:

Here is the solution hope it helps:)

5 0

1 year ago

At a given instant the bottom A of the ladder has an acceleration aA = 4 f t/s2 and velocity vA = 6 f t/s, both acting to the le

Nana76 [90]

Answer:

Acceleration=24.9ft^2/s^2

Angular acceleration=1.47rads/s

Explanation:

Note before the ladder is inclined at 30° to the horizontal with a length of 16ft

Hence angular velocity = 6/8=0.75rad/s

acceleration Ab=Aa +(Ab/a)+(Ab/a)t

4+0.75^2*16+a*16

0=0.75^2*16cos30°-a*16sin30°---1

Ab=0+0.75^2sin30°+a*16cos30°----2

Solving equation 1

(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s

Also from equation 2

Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2

6 0

2 years ago

This is PLZ HELP MY MOM GONNA GROUND ME!!!! Which step is part of a scientific investigation?

Novosadov [1.4K]

Answer:

evalating the soltion

Explanation:

4 0

3 years ago

A scientist at a space research center is doing research on near-Earth objects and determining the kinetic energy of a theoretic

Marysya12 [62]

<span>its kinetic energy is 7350kJ
</span>

Kinetic energy is given as = $\frac{1}{2} mv^{2}$

Now, m = 12 gms = 0.012 kg
And, velocity = 35 kilometers/second = 35000 m/sec

Kinetic energy is given as = $\frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}$
= 6 $10^{-2}$ ×1225 × $10^{6}$ m/ $s^{2}$
= 7350 kJ

6 0

3 years ago

Read 2 more answers

A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the c

icang [17]

Answer:

a. 900 J

b. 0.383

Explanation:

According to the question, the given data is as follows

Horizontal force = 150 N

Packing crate = 40.0 kg