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3 years ago

O 1. 12 moles

Chemistry

1 answer:

mars1129 [50]3 years ago

3 0

Answer:

$n_{H_2O}=5.94molH_2O$

Explanation:

Hello there!

In this case, according to the given question about stoichiometry, it is possible for us to calculate the required moles of water that will be produced by 12 grams of hydrogen, by using the molar mass of this reactant (2.02 g/mol as it is diatomic) and the 2:2 mole ratio in the chemical equation by solving the following setup:

$n_{H_2O}=12gH_2*\frac{1molH_2}{2.02gH_2} *\frac{2molH_2O}{2molH_2} \\\\n_{H_2O}=5.94molH_2O$

Regards!

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Answer:

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Explanation:

Chromic acid

pH = ?

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Step 1 - Set up Initial, Change, Equilibrium table;

H2CrO4 ⇄ H+ + HCrO4−

Initial - 0.078M 0 0

Change : -x +x +x

Equilibrium : 0.078-x x x

Step 2- Write Ka as Ratio of Conjugate Base to Acid

The dissociation constant Ka is [H+] [HCrO4−] / [H2CrO4].

Step 3 - Plug in Values from the Table

Ka = x * x / 0.078-x

Step 4 - Note that x is Related to pH and Calculate Ka

[H+] = 10^-pH.

Since x = [H+] and you know the pH of the solution,

you can write x = 10^-1.23.

It is now possible to find a numerical value for Ka.

Ka = (10^-1.23))^2 / (0.078 - 10^-1.23) = 0.00347 / 0.0191156

Ka = 0.1815

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Answer:

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Explanation:

Given that,

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