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Inga [223]
2 years ago
13

O 1. 12 moles

Chemistry
1 answer:
mars1129 [50]2 years ago
3 0

Answer:

n_{H_2O}=5.94molH_2O

Explanation:

Hello there!

In this case, according to the given question about stoichiometry, it is possible for us to calculate the required moles of water that will be produced by 12 grams of hydrogen, by using the molar mass of this reactant (2.02 g/mol as it is diatomic) and the 2:2 mole ratio in the chemical equation by solving the following setup:

n_{H_2O}=12gH_2*\frac{1molH_2}{2.02gH_2} *\frac{2molH_2O}{2molH_2} \\\\n_{H_2O}=5.94molH_2O

Regards!

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Nitrogen in plants and soil is changed into nitrogen compounds by _____.
grandymaker [24]

Answer:

A

Explanation:

because It's the process by which atmospheric nitrogen is converted either by a natural or an industrial means to form of nitrogen such as ammonia.

5 0
2 years ago
How many grams of NH3 are needed to provide the same number of molecules as in 0.85 grams of SF6?
solniwko [45]

Above it says the molecular weights are

NH3- 17g/mol and SF6-146 g/mol

Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.


<span><span><span>= 1mole / </span><span>146.048g *</span></span> 0.85g</span>


so we would need 0.00582000438 moles of NH3 to have the same number of molecules.

One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:


<span><span><span>= 17.030519999989988 g / </span><span>mole * </span></span>0.00582000438moles</span>


that equals 0.09911770099 grams.

so 0.09911770099 grams is the answer if you round that you get about 0.1 grams


3 0
3 years ago
Read 2 more answers
What is the percentage composition of each element in Fe(OH)3
Bezzdna [24]

Answer:

Fe =52.2%, O = 44.9%, H = 2.81%

Explanation:

Percentage composition is also known as percentage by mass.

First, find the Mr of the compound.

Mr of Fe(OH)₃ = 55.8 + (16 × 3) + (1 × 3)

= 106.8

Now Divide the mass of the element, as per the compound, by the Mr of the compound found and times that by 100.

% composition of Fe = \frac{55.8}{106.8} × 100 = 52.2%

% composition of O = \frac{16*3}{106.8} × 100 = 44.9%

[There are 3 oxygen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of oxygen with the number of atoms in the compound: 16×3 ]

% composition of H = \frac{1*3}{106.8} × 100 = 2.81%

[There are 3 hydrogen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of hydrogen with the number of atoms in the compound: 1×3 ]

3 0
2 years ago
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KiRa [710]
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4 0
3 years ago
Ph of 0.1M solution of acetic acid will be hogher than that of 0.1MHcl​
Aliun [14]

pH=-lg[H⁺]

[H⁺] is the molar concentration of hydrogen protons

both solutions have the same concentration of the monoprotic acid so they will both have the same pH

pH=-lg0.1=1 because 10 at the power of -1 is equal to 0.1 but the sign is changed

8 0
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