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SCORPION-xisa [38]
1 year ago
7

What would happen if evaporation does not take place in nature​

Chemistry
1 answer:
ivann1987 [24]1 year ago
6 0

Answer:

Evaporation is an important process in the water cycle. If there is no evaporation, there is no moisture in the atmosphere. As a result, clouds cannot form and there is no rain. Plants do not receive natural water and die. And there would be no rivers or lakes because their water comes from evaporation via rain or snow.

Explanation:

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In the measurement 0.503 L , which digit is the estimated digit ?
AysviL [449]
The estimated digit is dependent on the least count of the instrument being used. If the least count is 0.1 and the reading is between two divisions of the least count, then the estimated digit will be in the tenths, or 0.1 place. In this case, the estimated digit is 3, meaning the least count is 0.001.
5 0
3 years ago
If the magnetic energy stored by a 0.50 H inductor is 3.6 J, what is the current through it?
finlep [7]

The current passing through the inductor is 3.8 A. The correct option is D. 3.8 A

<h3>Energy stored in a magnetic field </h3>

From the question, we are to determine the current passing through the inductor.

From the formula, for the energy stored in a magnetic field

E = 1/2LI²

Where E is the energy

L is the inductance

and I is the current

From the given information,

E = 3.6 J

L = 0.50 H

Putting the parameters into the formula, we get

3.6 = 1/2 × 0.50 × I²

3.6 = 0.25 × I²

I² = 3.6 ÷ 0.25

I² = 14.4

I = √14.4

I = 3.7947

I ≅ 3.8 A

Hence, the current passing through the inductor is 3.8 A. The correct option is D. 3.8 A

Learn more on Energy stored in a magnetic field here: brainly.com/question/15244801

8 0
2 years ago
Can someone explain the alkali metals unit to me please? I am so confused and I have a test about this stuff. Not not only alkal
Nuetrik [128]
Alkali metals are the first column in the periodic table, alkaline earth metals are the second column. The following columns are transition metals up to the column with aluminum. These are non-metals, the second last column is halogens and the last is noble gases
6 0
3 years ago
What lens could get dirty with oil if you move the revolving nosepiece in the wrong direction after viewing under oil immersion?
xxMikexx [17]

From what we know, we can confirm that doing this may dirty and cause harm to your 40x lens.

<h3 /><h3>Why would this cause harm to your lens?</h3>

Oil immersion is a technique that can be quite handy when attempting to view hard-to-see specimens. However, This should be done only with lenses that are made specifically for this, so revolving the nosepiece in the wrong direction will expose the 40x lens to the oil, for which it is not designed, and may cause harm to the equipment.

Therefore, we can confirm that the 40x lens could get dirty with oil if you move the revolving nosepiece in the wrong direction after viewing it under oil immersion.

To learn more about microscopes visit:

brainly.com/question/507443?referrer=searchResults

3 0
2 years ago
The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

7 0
3 years ago
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