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2 years ago

Brownies, b are 30 more than half the calories of a piece of cake c, write an equation

Mathematics

2 answers:

Setler79 [48]2 years ago

8 0

Answer:

b = 30 + c ÷ 2

Step-by-step explanation:

b = brownies

c = cake

max2010maxim [7]2 years ago

4 0

The answer is 30>c(1/2) because brownies, b, is 30 MORE ,>, than half the calories, c.

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What is 19 1/2% of 62?

Alborosie

Answer:

12.09

done on calculator.

4 0

3 years ago

Read 2 more answers

the school store has1200 pendls in stock and sells and sells an average of 25 pencils per day the manager reorders when the numb

forsale [732]

Answer:

Number of pencils in stock = 1200

Average number of pencils sold by the manager per day = 24

Number of pencils that would be sold before reordering = 1200 - 500

= 700

Then

The number of days after which the manager will reorder = 700/24

= 29.16

So the manager has to reorder after about 30 days. Since the answer comes in fraction of more than 29 days, so it has to be 30 days. I hope the procedure is clear for your understanding.

Just to be clear, this answer is not mine, but I remember seeing this question so I just copied someones' answer. Still, you might find this helpful.

Here is the original brainly.com/question/955219

4 0

3 years ago

4√6 •√3 how do I show work for this because the answer is 2√12

Yuliya22 [10]

Answer:

$4 \sqrt{6} \times \sqrt{3} = 12 \sqrt{2}$

Step-by-step explanation:

We want to simplify the radical expression:

$4 \sqrt{6} \times \sqrt{3}$

We write √6 as √(2*3).

This implies that:

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2 \times 3} \times \sqrt{3}$

We now split the radical for √(2*3) to get:

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times \sqrt{3} \times \sqrt{3}$

We obtain a perfect square at the far right.

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times (\sqrt{3} )^{2}$

This simplifies to

$4 \sqrt{6} \times \sqrt{3} = 4 \sqrt{2} \times 3$

This gives us:

$4 \sqrt{6} \times \sqrt{3} = 4 \times 3 \sqrt{2}$

and finally, we have:

$4 \sqrt{6} \times \sqrt{3} = 12 \sqrt{2}$

5 0

3 years ago

Find the GCF 0f 12 and 18

melisa1 [442]

Answer:

Step-by-step explanation:

Using Euclid's algorithm, we divide the larger by the smaller. If the remainder is zero, the divisor is the GCF. Otherwise, we replace the larger with the remainder and repeat.

18 ÷ 12 = 1 r 6

12 ÷ 6 = 2 r 0 . . . . the GCF is 6

You can also factor the numbers and see what the common factors are.

18 = 2·3·3

12 = 2·2·3

The common factors are 2·3 = 6.

In the factorizations, we see 2 to powers of 1 and 2, and we see 3 to powers of 1 and 2. The GCF is the product of the common factors to their lowest powers: (2^1)(3^1) = (2)(3) = 6

8 0

2 years ago

Expand and simplify (x+5)(x-2)

salantis [7]

Answer:

${x}^{2} - x - 12 = (x + 3)(x - 4)$

${x}^{2} + 3x + 2 = (x + 2)(x + 1)$

${x}^{2} + 3x - 10 = (x + 5)(x - 2)$

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

${x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12$

${x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2$

${x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10$

I am joyous to assist you anytime.

8 0

2 years ago