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Blababa [14]
2 years ago
15

Explain how to solve the question over compound dependent events and explain how I got the answer.

Mathematics
1 answer:
AfilCa [17]2 years ago
6 0
Joe has a 1/2 probability of pulling a blue marble and 1/10 probability of pulling a red marble. 5/10+1/10= 6/10
6/10=3/5 there’s a 3/5 probability of pulling a blue than red marble
(i’m not sure if i completely understood i’m am very sorry if it’s wrong.)
You might be interested in
Help fast please In AGHI, GH || JK. Given that IJ= 20, GH=42, and JK = 24, find IG.
wolverine [178]

Answer:

55

Step-by-step explanation:

\frac{IJ}{JK} = \frac{JG}{GH}

\frac{20}{24} = \frac{JG}{42}

Cross multiply

|JG| = \frac{20  X 42}{24}

|JG| = 35

Therefore |IG| = |JG| + |IJ|

|IG| = 35 + 20

|IG| = 55

Please mark me brainiest if correct.

6 0
2 years ago
Deshaun the trainer has two solo workout plans that he offers his clients: Plan A and Plan B. Each client does either one or the
Juli2301 [7.4K]

Answer:

Plan A and plan B both lasts for 1.25 hours.

Step-by-step explanation:

Trainer has two solo workout plans Plan A and Plan B.

Let the trainer trains for plan A = x hours and for plan B = y hours

As per statement given in the question,

"Dueshan trained his Monday clients for a total of 10 hours"

Equation will be, 3x + 5y = 10 --------(1)

And other statement says,

"Dueshan trained his Tuesday clients for a total of 10 hours"

6x + 2y = 10

3x + y = 5

y = 5 - 3x ----------(2)

Replace the value of y in equation 2 from equation 1.

3x + 5(5 - 3x) = 10

3x + 25 - 15x = 10

25 - 12x = 10

12x = 25 - 10

12x = 15

x = \frac{15}{12}

x = 1.25 hours

From equation 1

y = 5 - 3×1.25

y = 5 - 3.75

y = 1.25 hours

Therefore, plan A and plan B both lasts for 1.25 hours.

6 0
3 years ago
22.5x−4.6=3.5 Solve correctly
Colt1911 [192]

Answer:

x = 0.36

Step-by-step explanation:

22.5x − 4.6 = 3.5

first, add the -4.6 over

22.5x = 8.1

then, divide 8.1 by 22.5

x = 0.36

best of luck!

8 0
3 years ago
Please answer this question
Bogdan [553]
C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p
3 0
3 years ago
Help, please. Formula for this problem?
dexar [7]
If I'm correct, x=16
7 0
3 years ago
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